JAVA:调整短信字符倒计时

时间:2015-03-08 19:31:26

标签: java string javafx sms countdown

我正在JavaFX8中开发一个SMS发送应用程序。 我需要帮助调整我的短信计数器功能。

一些背景信息:

一条短信可以包含160个字符。如果超过160个字符,则它将成为多部分SMS。所以第二条SMS可以包含146个字符,第三个包含153个字符。从第三条短信开始,每条短信可以包含153个字符。

所以它会像160 - > 146 - > 153 - > 153 - > 153 ......

现在我想从160倒数到0,然后从146倒数到0再到153倒数。

这是我到目前为止所做的:

smsComposeArea.textProperty().addListener((ObservableValue<? extends String> observable, String oldValue, String newValue) -> {
        //Replace all multiple whitspaces with one whitespace
        smsComposeArea.setText(smsComposeArea.getText().replaceAll("[^\\S\\r|\\n|\\r\\n]+", " "));
        //GSM 03.38 Extended charset ^{}\[~]|€ take up 2 characters - count them as 2 chars. Replace multiple tabs, newlines, whitespaces with one.
        int charCount = smsComposeArea.getText().replaceAll("[\\^{}\\\\\\[~\\]|€]{1}", "$0$0").replaceAll("(\\r|\\n|\\r\\n|\\s)+", " ").length();

        int countDown;
        if(smsComposeArea.getText() == null && smsComposeArea.getText().trim().isEmpty()) {
            lblCharCounter.setText("160");
        }
        else if(charCount >= 1 && charCount <= 160) {
            countDown = 160 - charCount;
            lblCharCounter.setText(Integer.toString(countDown));
        }
        else if(charCount >= 160 && charCount <= 306) {
            countDown = 146 - (charCount - 160);
            lblCharCounter.setText(String.format("2 SMS %s", Integer.toString(countDown)));
        }
        else if(charCount >= 306 && charCount <= 459) {
            countDown = 153 - (charCount - 306);
            lblCharCounter.setText(String.format("3 SMS %s", Integer.toString(countDown)));
        }
        else if(charCount >= 459 && charCount <= 612) {
            countDown = 153 - (charCount - 459);
            lblCharCounter.setText(String.format("4 SMS %s", Integer.toString(countDown)));
        }
        else if(charCount >= 612 && charCount <= 765) {
            countDown = 153 - (charCount - 612);
            lblCharCounter.setText(String.format("5 SMS %s", Integer.toString(countDown)));
        }
        else if(charCount >= 765 && charCount <= 918) {
            countDown = 153 - (charCount - 765);
            lblCharCounter.setText(String.format("6 SMS %s", Integer.toString(countDown)));
        }
        else if(charCount >= 918 && charCount <= 1071) {
            countDown = 153 - (charCount - 918);
            lblCharCounter.setText(String.format("7 SMS %s", Integer.toString(countDown)));
        }
        else if(charCount >= 1071 && charCount <= 1224) {
            countDown = 153 - (charCount - 1071);
            lblCharCounter.setText(String.format("8 SMS %s", Integer.toString(countDown)));
        }
        else if(charCount >= 1224 && charCount <= 1377) {
            countDown = 153 - (charCount - 1224);
            lblCharCounter.setText(String.format("9 SMS %s", Integer.toString(countDown)));
        }
        else if(charCount >= 1377 && charCount <= 1530) {
            countDown = 153 - (charCount - 1377);
            lblCharCounter.setText(String.format("10 SMS %s", Integer.toString(countDown)));
        }


    }
);

它按预期工作,但我认为应该有更复杂或动态的方式来显示倒计时。在我看来,IF语句太多了。

感谢任何帮助!

3 个答案:

答案 0 :(得分:1)

https://github.com/messente/sms-length-calculator提供免费的短信长度计算库,用于检测编码,并在多部分短信中为扩展的gsm 7bit字符集处理尾随转义字符。

您还可以在http://messente.com/documentation/sms-length-calculator

学习和试验在线短信长度计算器

答案 1 :(得分:0)

我对SMS协议一无所知,但假设您的背景信息正确,您可以这样做:

IntegerBinding textLength = Bindings.length(smsComposeArea.textProperty());

IntegerBinding numberOfSms = Bindings.createIntegerBinding(() -> {
    if (textLength.get() <= 160) {
        return 1 ;
    } else if (textLength.get() <= 306) {
        return 2 ;
    } else {
        return 3 + (textLength.get() - 307) / 153 ;
    }
}, textLength);

IntegerBinding remainingChars = Bindings.createIntegerBinding(() -> {
    if (numberOfSms.get() == 1) {
        return 160 - textLength.get() ;
    } else if (numberOfSms.get() == 2) {
        return 306 - textLength.get() ;
    } else {
        return 306 + (numberOfSms.get() - 2) * 153 - textLength.get() ;
    }
}, numberOfSms, textLength);

lblCharCounter.textProperty().bind(Bindings.format("%d SMS %d", numberOfSms, remainingChars));

如果@ RealSkeptic的答案中的计算是正确的,那么你可以

IntegerBinding textLength = Bindings.length(smsComposeArea.textProperty());

IntegerBinding numberOfSms = Bindings.createIntegerBinding(() -> {
    if (textLength.get() <= 160) {
        return 1 ;
    } else {
        return 1 + (textLength.get() - 1) / 153 ;
    }
}, textLength);

IntegerBinding remainingChars = Bindings.createIntegerBinding(() -> {
    if (numberOfSms.get() == 1) {
        return 160 - textLength.get() ;
    } else {
        return numberOfSms.get() * 153 - textLength.get() ;
    }
}, numberOfSms, textLength);

lblCharCounter.textProperty().bind(Bindings.format("%d SMS %d", numberOfSms, remainingChars));

或者可能(总共有if个陈述)

IntegerBinding textLength = Bindings.length(smsComposeArea.textProperty());

BooleanBinding singleSMS = textLength.lessThanOrEqualTo(160);

IntegerBinding numberOfSms = Bindings.when(singleSMS).then(1).otherwise(
    textLength.subtract(1).divide(153).add(1));
IntegerBinding remainingChars = Bindings.when(singleSMS).then(textLength.subtract(160).multiply(-1)).otherwise(
    numberOfSms.multiply(153).subtract(textLength));

lblCharCounter.textProperty().bind(Bindings.format("%d SMS %d", numberOfSms, remainingChars));

取决于您喜欢的风格。

答案 2 :(得分:0)

假设您使用8位SMS编码,其中每个字符占用一个字节,会发生什么:

  • 如果邮件的长度达到(包括)160个字符,则只有一条邮件。剩下的字符是160 - n,其中n是键入的字符数。
  • 如果消息的长度超过160个字符(161及以上),则给定7字节的扩展UDH,每个段的长度为153个字符。这意味着⌈n/153⌉段。并且当前段结束前的字符数为⌈n/153⌉×153-n。

这意味着您根本不应该有很多“if”语句:

if ( charCount <= 160 ) {
    nSegments = 1;
    countDown = 160 - charCount;
} else if ( charCount % 153 == 0 ) {
    nSegments = charCount / 153;
    countDown = 0;
} else {
    nSegments = charCount / 153 + 1;
    countDown = nSegments * 153 - charCount;
}
lblCharCounter.setText(String.format("%d SMS %d", nSegments, countDown) );