Question

可能回答很简单，但我无法弄明白。我尝试使用以下代码添加联系人，但仅限于＆＃34; contact_0＆＃34;存在于联系人列表中。你知道这段代码有什么问题吗？

 public void myMethod(){

    for (int i = 0; i < 5; i++) {
        ArrayList<ContentProviderOperation> ops = new ArrayList<ContentProviderOperation>();
        ops.add(ContentProviderOperation
                .newInsert(ContactsContract.RawContacts.CONTENT_URI)
                .withValue(ContactsContract.RawContacts.ACCOUNT_TYPE,
                        null)
                .withValue(ContactsContract.RawContacts.ACCOUNT_NAME,
                        null)
                .withValue(ContactsContract.RawContacts.AGGREGATION_MODE,
                        ContactsContract.RawContacts.AGGREGATION_MODE_DISABLED).build());

        // ------------------------------------------------------ Name

        ops.add(ContentProviderOperation
                .newInsert(ContactsContract.Data.CONTENT_URI)
                .withValueBackReference(
                        ContactsContract.Data.RAW_CONTACT_ID, i)
                .withValue(
                        ContactsContract.Data.MIMETYPE,
                        ContactsContract.CommonDataKinds.StructuredName.CONTENT_ITEM_TYPE)
                .withValue(
                        ContactsContract.CommonDataKinds.StructuredName.DISPLAY_NAME,
                        "contact_"+i).build());

        // ------------------------------------------------------ Work
        // Number

        ops.add(ContentProviderOperation
                .newInsert(ContactsContract.Data.CONTENT_URI)
                .withValueBackReference(
                        ContactsContract.Data.RAW_CONTACT_ID, i)
                .withValue(
                        ContactsContract.Data.MIMETYPE,
                        ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE)
                .withValue(
                        ContactsContract.CommonDataKinds.Phone.NUMBER,
                        "01 62384")
                .withValue(
                        ContactsContract.CommonDataKinds.Phone.TYPE,
                        ContactsContract.CommonDataKinds.Phone.TYPE_WORK)
                .build());



        try {
            getContentResolver().applyBatch(ContactsContract.AUTHORITY, ops);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

任何想法的人？

提前感谢您提供任何帮助

Answer 1

public void myMethod(){

    for (int i = 0; i < 5; i++) {
        ArrayList<ContentProviderOperation> ops = new ArrayList<ContentProviderOperation>();
        ops.add(ContentProviderOperation
                .newInsert(ContactsContract.RawContacts.CONTENT_URI)
                .withValue(ContactsContract.RawContacts.ACCOUNT_TYPE,
                        null)
                .withValue(ContactsContract.RawContacts.ACCOUNT_NAME,
                        null)
                .withValue(ContactsContract.RawContacts.AGGREGATION_MODE,
                        ContactsContract.RawContacts.AGGREGATION_MODE_DISABLED).build());

        // ------------------------------------------------------ Name

        ops.add(ContentProviderOperation
                .newInsert(ContactsContract.Data.CONTENT_URI)
                .withValueBackReference(
                        ContactsContract.Data.RAW_CONTACT_ID, 0)
                .withValue(
                        ContactsContract.Data.MIMETYPE,
                        ContactsContract.CommonDataKinds.StructuredName.CONTENT_ITEM_TYPE)
                .withValue(
                        ContactsContract.CommonDataKinds.StructuredName.DISPLAY_NAME,
                        "contact_"+i).build());

        // ------------------------------------------------------ Work
        // Number

        ops.add(ContentProviderOperation
                .newInsert(ContactsContract.Data.CONTENT_URI)
                .withValueBackReference(
                        ContactsContract.Data.RAW_CONTACT_ID, 0)
                .withValue(
                        ContactsContract.Data.MIMETYPE,
                        ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE)
                .withValue(
                        ContactsContract.CommonDataKinds.Phone.NUMBER,
                        "01 62384")
                .withValue(
                        ContactsContract.CommonDataKinds.Phone.TYPE,
                        ContactsContract.CommonDataKinds.Phone.TYPE_WORK)
                .build());



        try {
            getContentResolver().applyBatch(ContactsContract.AUTHORITY, ops);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

请在每次插入操作中使用RAW_CONTACT_ID 0。这对我有用。

向Android添加多个联系人

1 个答案: