Question

我的页面上有一个评论功能，但我正在尝试添加一些功能。

like-，report-和delete按钮

但似乎我的代码不必要复杂。

    function comment_func_bar($how_many,$comment_id,$uid)
    {
      // connect to the database
    //include_once('config.php');
     $mysqli = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME);

     // get the records from the database
     $result=$mysqli->query("SELECT `uid_fk` FROM `comment_likes` WHERE `comment_id_fk` = '".$comment_id."'");
     $row = mysqli_fetch_row($result);
     if($result->num_rows === 0) //If no likes
     {
        $how_many='';
     } else if(($result->num_rows === 1) && ($row[0] === "$uid")) { //If one like, and that one like is "you"
    $how_many = "You like, "; //Should be $_SESSION["user_name"] or what ever
     }else if($result->num_rows === 1) //If one like, and its not "you"
     {
    $other_user_id=$row[0];
    $result=$mysqli->query("SELECT `user_name` FROM `users` WHERE `user_id` = '".$other_user_id."'");
    $row = mysqli_fetch_row($result);
    $how_many=$row[0];
     }

     //Check if the user already have liked a comment
//http://stackoverflow.com/questions/10164035/how-to-find-specific-row-in-mysql-query-result
    while($row = mysqli_fetch_row($result))
    {
      if($row === $uid)
      {
        //row found, do processing ...
        //reset pointer and break from loop
                echo '<p id="txtHint"><small><a href="" class="clickable">' . $how_many .' Unlike</a> - <a href="">Report</a> - <a href="#" class="del_button" id="del-'.$comment_id.'">Delete</a></small></p>';
        if(!mysql_data_seek($result, 0))
          //Row not found
                  echo '<p id="txtHint"><small><a href="" class="clickable">' . $how_many .' Like</a> - <a href="">Report</a> - <a href="#" class="del_button" id="del-'.$comment_id.'">Delete</a></small></p>';
        break;
      }
    }
    }

但实际问题是在底部。

我正在尝试为用户$ uid搜索行，以确定该用户是否已经喜欢。但我无法让它发挥作用。

它什么都不返回，没有错误，什么都没有！

Answer 1

自己解决，谢谢你

希望这可以为下一个试图做同样事情的人提供一些想法！

您实际上可以在代码中找到帮助我的线程。和ofc http://php.net/manual/en/control-structures.if.php

    function comment_func_bar($how_many,$comment_id,$uid)
{
  // connect to the database
//include_once('config.php');
 $mysqli = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME);

 // get the records from the database
 $result=$mysqli->query("SELECT `uid_fk` FROM `comment_likes` WHERE `comment_id_fk` = '".$comment_id."'");
 $row = mysqli_fetch_row($result);

 if($result->num_rows === 0) //If no likes
 {
    $how_many='';
 } else if(($result->num_rows === 1) && ($row[0] === "$uid")) { //If one like, and that one like is "you"
$how_many = "You like, "; //Should be $_SESSION["user_name"] or what ever
 }else if($result->num_rows === 1) //If one like, and its not "you"
 {
$other_user_id=$row[0];
$result=$mysqli->query("SELECT `user_name` FROM `users` WHERE `user_id` = '".$other_user_id."'");
$row = mysqli_fetch_row($result);
$how_many=$row[0];
 }

 //Check if the user already have liked a comment
 //http://stackoverflow.com/questions/4037145/mysql-how-to-select-rows-where-value-is-in-array
 ////http://stackoverflow.com/questions/10164035/how-to-find-specific-row-in-mysql-query-result
// $row = mysqli_fetch_row($result);
$result=$mysqli->query("SELECT `uid_fk` FROM `comment_likes` WHERE `comment_id_fk` = '".$comment_id."'");
  if(!cycelUser($result,$uid))
  {        
            echo '<p id="txtHint"><small><a href="" class="clickable">' . $how_many .' Like</a> - <a href="">Report</a> - <a href="#" class="del_button" id="del-'.$comment_id.'">Delete</a></small></p>';

        }else {
            echo '<p id="txtHint"><small><a href="" class="clickable">' . $how_many .' Unlike</a> - <a href="">Report</a> - <a href="#" class="del_button" id="del-'.$comment_id.'">Delete</a></small></p>';
}
  }


// Cycel throu the uid_fk from comment_likes to find if the user have liked it before!
  // Not a very nice solution, but it works (apperently)
function cycelUser ($result,$uid)
{
    while ( $row = mysqli_fetch_assoc( $result ) ) { //_array or _assoc whatever
        if ( $row['uid_fk'] == $uid ) {
            mysqli_data_seek( $result, 0 );
            return $row;
        }
    }
}

我的comment_func_bar函数无效

1 个答案: