当我在index.html文件中进行更改时，我的网页没有更新

Question

我是初学者使用gulp.js，我的网页不受我在index.html文件中所做的更改的影响

我看到了这个错误

    server.changed(e.path);
       ^
TypeError: undefined is not a function

我尝试对gulp-livereload进行更改，但我无法做到。

my gulpfile.js

var gulp = require('gulp'),
    gutil = require('gulp-util'),
    uglify = require('gulp-uglify'),
    concat = require('gulp-concat'),
    livereload = require('gulp-livereload'),
    lr = require('tiny-lr'),
    server = lr();

var jsSources = [
  'components/scripts/scriptOne.js',
  'components/scripts/scriptTwo.js'
];

gulp.task('js', function() {
  gulp.src(jsSources)
          .pipe(uglify())
          .pipe(concat('script.js'))
          .pipe(gulp.dest('js'));
});

gulp.task('watch', function() {
  var server = livereload();
  gulp.watch(jsSources, ['js']);
  gulp.watch(['js/script.js', '*.html'], function(e) {
    server.changed(e.path);
  });
});

gulp.task('default', ['js', 'watch']);

var gulp = require('gulp'),
    gutil = require('gulp-util'),
    uglify = require('gulp-uglify'),
    concat = require('gulp-concat'),
    livereload = require('gulp-livereload'),
    lr = require('tiny-lr'),
    server = lr();

var jsSources = [
  'components/scripts/scriptOne.js',
  'components/scripts/scriptTwo.js'
];

gulp.task('js', function() {
  gulp.src(jsSources)
          .pipe(uglify())
          .pipe(concat('script.js'))
          .pipe(gulp.dest('js'));
});

gulp.task('watch', function() {
  livereload.listen()
  var server = livereload();
  gulp.watch(jsSources, ['js']);
  gulp.watch(['js/script.js', '*.html'], function(e) {
    server.changed(e.path);
  });
});

gulp.task('default', ['js', 'watch']);

Answer 1

Gulp插件（如LiveReload）经常更新，在这种情况下，会导致影响Lynda.com课程的细微差别。他们在这里发布了更正：

https://github.com/planetoftheweb/coffeescript