Question

在我的asp gird asp网格分页不工作是什么问题是我的代码请帮帮我..问题是当我点击分页项目页面没有回帖..

这是我的aspx代码：

<asp:GridView ID="GridView1" Font-Size = "11pt" OnRowCommand="GridView1_RowCommand" AllowPaging="true" AllowSorting="true" PagerSettings-Visible="true" PageSize="4" CssClass="footable" runat="server" AutoGenerateColumns="false"
        Style="max-width: 500px" DataKeyNames="Id" EnableViewState="true" OnPageIndexChanging="GridView1_PageIndexChanging">
        <Columns>
            <asp:ButtonField CommandName="Edit" ButtonType="Image" ImageUrl="~/image/redit.png" />
            <asp:BoundField DataField="ProductName" HeaderText="Product Name" />
            <asp:BoundField DataField="ProductDescription" HeaderText="Description" />
            <asp:TemplateField>
                <ItemTemplate>
                    <img src='data:image/jpg;base64,<%# Eval("ProductImage") != System.DBNull.Value ? Convert.ToBase64String((byte[])Eval("ProductImage")) : string.Empty %>' alt="image" height="80" width="80" />
                </ItemTemplate>
            </asp:TemplateField>
            <asp:ButtonField CommandName="Delete" ButtonType="Image" ImageUrl="~/image/rdelete.png" />
        </Columns>
            <PagerStyle HorizontalAlign = "Right"  />
     </asp:GridView>
    <link href="https://cdnjs.cloudflare.com/ajax/libs/jquery-footable/0.1.0/css/footable.min.css"
        rel="stylesheet" type="text/css" />
    <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
    <script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/jquery-footable/0.1.0/js/footable.min.js"></script>
    <script type="text/javascript">
        $(function () {
            $('[id*=GridView1]').footable();
        });
    </script>

这是我的aspx.cs

protected void Page_Load(object sender, EventArgs e)
{
    if (!this.IsPostBack)
    {
        LoadGrid();
    }
}

protected void GridView1_RowCommand(object sender, GridViewCommandEventArgs e)
{
    int rowIndex = int.Parse(e.CommandArgument.ToString());
    string val = (string)this.GridView1.DataKeys[rowIndex]["Id"];

    if (e.CommandName == "Edit")
    {

    }
    else if (e.CommandName == "Delete")
    {

    }
}

public void LoadGrid()
{
    try
    {
        BusinessLogic.clsGeneral objGen = new BusinessLogic.clsGeneral();
        string strquery = "select * from Products where status = 1";
        DataTable dt = objGen.ExecuteQueryReturnDatatable(strquery);
        GridView1.DataSource = dt;
        GridView1.DataBind();
        GridView1.HeaderRow.TableSection = TableRowSection.TableHeader;
    }
    catch (Exception)
    {
    }

}

protected void GridView1_PageIndexChanging(object sender, GridViewPageEventArgs e)
{
    GridView1.PageIndex = e.NewPageIndex;
    GridView1.DataBind();
}

Answer 1

尝试这样：

您需要在PageIndexChanging事件

中再次绑定GridView

protected void GridView1_PageIndexChanging(object sender, GridViewPageEventArgs e)
{
    GridView1.PageIndex = e.NewPageIndex;
    LoadGrid();
}

Answer 2

将数据源agin添加到您的分页中，

尝试从您的代码中替换以下代码段。

protected void GridView1_PageIndexChanging(object sender, GridViewPageEventArgs e)
{
  GridView1.PageIndex = e.NewPageIndex;
  BusinessLogic.clsGeneral objGen = new BusinessLogic.clsGeneral();
  string strquery = "select * from Products where status = 1";
  DataTable dt = objGen.ExecuteQueryReturnDatatable(strquery);
  GridView1.DataSource = dt;
  GridView1.DataBind();
}

这里仍有一些要点

避免inLine查询，这看起来不太好

尽管再次调用数据绑定，你也可以使用其他一些技巧。

在Sql中，永远不会返回*（全部），只返回你需要的列集，*不是很好的做法。例如。从....选择姓名，地址，电话，而不是选择* ...

Answer 3

{{serviceData | async}}

asp网格视图分页不起作用

3 个答案: