Question

所以我有一个文本文件：

5f6
2f8
2f2

我正在读取值：5,6,2,8,2,2其中前两个数字总是行x列，然后我试图回想起文件值的矩形（这可以正常工作，但是在运行程序之后，当它打印出来时，它会出现故障）。

#include <stdio.h>
#include <ncurses.h>
#include <stdlib.h>
#include <string.h>

int main(int argc, char * argv[])
{

    initscr();
    cbreak();
    noecho();

    char str[100];
    static char * row;
    static char * col;
    static int i;
    static int j;
    static int k;
    static int x; 
    static int y;
    int count = 0;

    FILE* file;
    file = fopen(argv[1],"r");

    if(file == NULL)
    {
        mvprintw(0,0,"File returns null pointer");
        exit(1);
    }

    while(!feof(file))
    {
        fgets(str,100,file);
        row = strtok(str,"x");
        col = strtok(NULL," \n");

        x = atol(row);
        y = atol(col);

        for(j=0;j<x;j++)
        {
            for(k=0;k<y;k++)
            {
                mvprintw(k+5,j+5+count,".");
                refresh(); //Space out drawing each rectangle? so they don't overlap
            }
        }
        count+=5;
    }

    fclose(file);
    getch();
    endwin();
    return (0);
}

我不确定如何继续这里，我将如何消除这个seg错误，并可能将结果绘制出来（计数变量似乎没有这样做）。

Answer 1

您的细分错误是因为您没有检查strtok()是否返回NULL并且仍然使用atol()取消引用指针，这是如何正确执行此操作的示例

#include <stdio.h>
#include <ncurses.h>
#include <stdlib.h>
#include <string.h>

int main(int argc, char * argv[])
{
    char  str[100];
    int   j;
    int   k;
    int   count;
    FILE *file;

    file = fopen(argv[1],"r");
    if (file == NULL)
     {
        mvprintw(0, 0, "File returns null pointer");
        return 1;
     }

    initscr();
    cbreak();
    noecho();

    count = 0;
    while(fgets(str, sizeof(str), file) != NULL)
     {
        char *endptr;
        char *row;
        char *col;
        int   x;
        int   y;

        row = strtok(str, "f");
        if (row == NULL)
         {
            fprintf(stderr, "`%s' does not contain `f'\n", str);
            continue;
         }
        col = strtok(NULL, " \n");
        if (col == NULL)
         {
            fprintf(stderr, "`%s' caused an unexpected error\n", str);
            continue;
         }
        x = strtol(row, &endptr, 10);
        if (*endptr != '\0')
         {
            fprintf(stderr, "Cannot convert `%s' to integer\n", row);
            continue;
         }
        y = strtol(col, &endptr, 10);
        if (*endptr != '\0')
         {
            fprintf(stderr, "Cannot convert `%s' to integer\n", col);
            continue;
         }
        for (j = 0 ; j  < x ; j++)
         {
            for (k = 0 ; k < y ; k++)
             {
                mvprintw(k + 5, j + 5 + count, ".");
                refresh();
             }
         }
        count+=5;
     }

    fclose(file);
    getch();
    endwin();

    return 0;
}

读入文件会导致seg错误

1 个答案: