我正在尝试使用angularjs创建一个twitter克隆。 目前,数据在数组中被模拟。
如何到达嵌套数组? 我找到的唯一错误是
"无法阅读财产'#'未定义"
该数组名为users,其中包含有关用户的所有数据,包括嵌套数组中的推文
或者有没有办法使用user [x] .name之类的东西来达到某个项目,其中x是数组索引
HTML看起来像这样:
<div ng-repeat="user in users">
<div class="row" >
<div class="col-md-9">
<fieldset>
<legend>S0</legend>
<img src="{{user.image}}" alt="no image" style="float:left;width:50px;height:50px;margin-right:20px;">
<h1>{{user.name}}</h1>
</fieldset>
</div>
<div class="col-md-3">
<fieldset>
<legend>S2 Details</legend>
Name: {{user.name}}<br>
Location: {{user.location}}<br>
Web: {{user.web}}<br>
Bio: {{user.bio}}
</fieldset>
</div>
<div class="col-md-9">
<fieldset>
<legend>S1 Tweets</legend>
<ul>
<li ng-repeat="tweet in user.tweets">
{{user.name}}
{{user.tweet.date}}
<br>
{{users[1].tweet.text}}
</li>
</ul>
</fieldset>
</div>
<div class="col-md-3">
<fieldset>
<legend>S3</legend>
</fieldset>
</div>
<div class="col-md-3">
<fieldset>
<legend>S4 Following</legend>
</fieldset>
</div>
</div>
数据/数组的存储方式如下:
angular.module('myApp.tweets', ['ngRoute'])
.config(['$routeProvider', function ($routeProvider) {
$routeProvider.when('/tweets', {
templateUrl: 'tweets/tweets.html',
controller: 'tweetsCtrl'
});
}])
.controller('tweetsCtrl', ['$scope', function ($scope) {
$scope.users[
{id: "1",
name: "userAbc",
location: "hugecity",
web: "www.abc.nl",
bio: "Hey welcome on my profile",
image: "http://upload.wikimedia.org/wikipedia/commons/a/ac/No_image_available.svg",
tweets: [
{date: "08/03/2015", text: "bericht 4"},
{date: "07/03/2015", text: "bericht 3"},
{date: "06/03/2015", text: "bericht 2"},
{date: "05/03/2015", text: "bericht 1"}
]},
{id: "2",
name: "userDef",
location: "hugecity",
web: "www.abc2.nl",
bio: "Hey welcome to my profile",
image: "http://upload.wikimedia.org/wikipedia/commons/a/ac/No_image_available.svg",
tweets: [
{date: "08/03/2015", text: "bericht 4"},
{date: "07/03/2015", text: "bericht 3"},
{date: "06/03/2015", text: "bericht 2"},
{date: "05/03/2015", text: "bericht 1"}
]}
];
}]);
答案 0 :(得分:0)
您可以将$scope.users
更改为以下代码:
$scope.users = [
{id: "1",
name: "userAbc",
location: "hugecity",
web: "www.abc.nl",
bio: "Hey welcome on my profile",
image: "http://upload.wikimedia.org/wikipedia/commons/a/ac/No_image_available.svg",
tweets: [
{date: "08/03/2015", text: "bericht 4"},
{date: "07/03/2015", text: "bericht 3"},
{date: "06/03/2015", text: "bericht 2"},
{date: "05/03/2015", text: "bericht 1"}
]},
{id: "2",
name: "userDef",
location: "hugecity",
web: "www.abc2.nl",
bio: "Hey welcome to my profile",
image: "http://upload.wikimedia.org/wikipedia/commons/a/ac/No_image_available.svg",
tweets: [
{date: "08/03/2015", text: "bericht 4"},
{date: "07/03/2015", text: "bericht 3"},
{date: "06/03/2015", text: "bericht 2"},
{date: "05/03/2015", text: "bericht 1"}
]}
];
答案 1 :(得分:0)
在$ scope.users
之后,您的类型缺少“=”$scope.users=[
{id: "1",
name: "userAbc",
location: "hugecity",
web: "www.abc.nl",
bio: "Hey welcome on my profile",
image: "Hello",
tweets: [
{date: "08/03/2015", text: "bericht 4"},
{date: "07/03/2015", text: "bericht 3"},
{date: "06/03/2015", text: "bericht 2"},
{date: "05/03/2015", text: "bericht 1"}
]},
{id: "2",
name: "userDef",
location: "hugecity",
web: "www.abc2.nl",
bio: "Hey welcome to my profile",
image: "kjh",
tweets: [
{date: "08/03/2015", text: "bericht 4"},
[enter link description here][1] {date: "07/03/2015", text: "bericht 3"},
{date: "06/03/2015", text: "bericht 2"},
{date: "05/03/2015", text: "bericht 1"}
]}
];
}]);