当我运行此代码时,我只是尝试使用轮班详细信息和员工填充列表,我已经在超类中预先制作了一个员工生成器,所以我认为不重复代码是一种好习惯。我可以创建移位数组列表并填充它,但每次创建移位对象时,它都会显示EmployeeSheet
字段。
继承人EmployeeSheet
班:
import java.util.*;
public class EmployeeSheet
extends Employee {
private ArrayList<Employee> empSheet;
private ProductionWorker pworker;
private ShiftSupervisor sworker;
/**
* Constructs a list of randomly selected employees and displays the list.
*/
public EmployeeSheet() {
empSheet = new ArrayList<Employee>();
Random empPicker = new Random();
for (int i = 0; i < 20; i++) {
int id = empPicker.nextInt(20);
if (id < 12) // roll for production worker
{
System.out.println("Adding Production Worker");
empSheet.add(generateProductionWorker());
} else //roll for Shift supervisor
{
System.out.println("Adding Shift supervisor");
empSheet.add(generateShiftSupervisor());
}
}
Iterator iterator = empSheet.iterator();
while (iterator.hasNext()) {
System.out.println("");
System.out.println(iterator.next());
}
}
/**
* Generates a Production Worker
* @return The fields that make up a Production worker
*/
public ProductionWorker generateProductionWorker() {
Random rng = new Random();
int numberOfEmployeeNames = Ename.length;
ProductionWorker tempPworker = new ProductionWorker();
String employeeName = Ename[rng.nextInt(numberOfEmployeeNames)];
tempPworker.setEmployeeName(employeeName);
int numberOfEmployeeNumbers = Empnum.length;
String employeeNumber = Empnum[rng.nextInt(numberOfEmployeeNumbers)];
tempPworker.setEmployeeNumber(employeeNumber);
int yearHired = rng.nextInt(35) + 1980;
tempPworker.setEmployeehireyear(yearHired);
double weeklySalary = rng.nextInt((100) * 100);
tempPworker.setEmployeeweeklyearning(weeklySalary);
int hourlyRate = rng.nextInt(20) + 10;
tempPworker.setHourlyRate(hourlyRate);
pworker = tempPworker;
return tempPworker;
}
/**
* Generates a ShiftSupervisor employee
* @return the Fields that make up a shift supervisor
*/
public ShiftSupervisor generateShiftSupervisor() {
Random ran = new Random();
int numberOfEmployeeNames = Ename.length;
ShiftSupervisor tempSworker = new ShiftSupervisor();
String employeeName = Ename[ran.nextInt(numberOfEmployeeNames)];
tempSworker.setEmployeeName(employeeName);
int numberOfEmployeeNumbers = Empnum.length;
String employeeNumber = Empnum[ran.nextInt(numberOfEmployeeNumbers)];
tempSworker.setEmployeeNumber(employeeNumber);
int yearHired = ran.nextInt(35) + 1900;
tempSworker.setEmployeehireyear(yearHired);
double weeklySalary = ran.nextInt((100) * 100);
tempSworker.setEmployeeweeklyearning(weeklySalary);
int goalsMet = ran.nextInt(100) + 1;
tempSworker.setGoalsCleared(goalsMet);
double yearlySalary = ran.nextInt((40000) + 40000);
tempSworker.setYearlySalary(yearlySalary);
sworker = tempSworker;
return tempSworker;
}
public int checkSize() {
return empSheet.size();
}
}
继承班班:
import java.util.*;
public class Shift
extends EmployeeSheet {
private ArrayList<Employee> shiftDetails;
private ProductionWorker pWorker;
private ShiftSupervisor sWorker;
public Shift() {
this.generateShift();
}
// instance variables - replace the example below with your own
/**
* Constructor for objects of class Shift
*/
public void generateShift() {
shiftDetails = new ArrayList();
Random supervisorCount = new Random();
int ssID = supervisorCount.nextInt(3);
for (int i = 0; i < ssID; i++) {
shiftDetails.add(this.generateShiftSupervisor());
}
Random productionCount = new Random();
int prodID = productionCount.nextInt(15) + 5;
for (int d = 0; d < prodID; d++) {
shiftDetails.add(this.generateProductionWorker());
}
}
public ProductionWorker generateProductionWorker() {
pWorker = super.generateProductionWorker();
return pWorker;
}
public ShiftSupervisor generateShiftSupervisor() {
sWorker = super.generateShiftSupervisor();
return sWorker;
}
}
为什么会发生这种情况?
答案 0 :(得分:4)
为什么子类运行超类构造函数?
构造基础对象。否则它将是未构造的,继承语义将是不完整的。
每当我创建shift对象时,它都会显示EmployeeSheet字段。
因为EmployeeSheet的构造函数显示这些字段。
为什么会发生这种情况?
因为Shift扩展了EmployeeSheet。
答案 1 :(得分:3)
您在Java中编写的任何构造函数都是从对另一个构造函数的调用开始的。如果你没有明确地写它,那么编译器会为你编写以下行作为构造函数的第一行:
super();
这意味着为了构造任何实例,您需要首先构造父类的实例(除了没有父类的Object类)。
从Object Oriented Programming的角度来看,这是有道理的,因为当A继承自B时,它意味着A“是一个”B,具有某种特定的状态或行为。在您的情况下,似乎您没有使用继承来描述“是一个”关系,这可能是一个设计错误。
我的意思是,似乎EmployeeSheet“不是”员工。您最好仅使用Composition来建模此关系。