Question

我正在与联接表设置一对多单向关系，如下所述：http://doctrine-orm.readthedocs.org/en/latest/reference/association-mapping.html#one-to-many-unidirectional-with-join-table

我有一个名为TestEntity的实体和一个名为testOptionalProperty的实体。当我尝试保留我的Entity对象时，我收到错误

捕获致命错误：参数1传递给 Doctrine \ Common \ Collections \ ArrayCollection :: __ construct（）必须是类型数组，给定对象，调用 /Users/dave/Desktop/doctrine-fun/vendor/doctrine/orm/lib/Doctrine/ORM/UnitOfWork.php 在第555行并定义

以下是我的实体：

TestEntity.php

namespace AppBundle\Entity;

use Doctrine\ORM\Mapping as ORM;

/**
 * TestEntity
 */
class TestEntity
{
    /**
     * @var integer
     */
    private $id;

    /**
     * @var string
     */
    private $name;

    private $testOptionalProperty;

    /**
     * @return mixed
     */
    public function getTestOptionalProperty()
    {
        return $this->testOptionalProperty;
    }

    /**
     * @param mixed $testOptionalProperty
     */
    public function setTestOptionalProperty($testOptionalProperty)
    {
        $this->testOptionalProperty = $testOptionalProperty;
    }

    /**
     * Get id
     *
     * @return integer 
     */
    public function getId()
    {
        return $this->id;
    }

    /**
     * Set name
     *
     * @param string $name
     * @return TestEntity
     */
    public function setName($name)
    {
        $this->name = $name;

        return $this;
    }

    /**
     * Get name
     *
     * @return string 
     */
    public function getName()
    {
        return $this->name;
    }
}

TestOptionalProperty.php

<?php

namespace AppBundle\Entity;

use Doctrine\ORM\Mapping as ORM;

/**
 * TestOptionalProperty
 */
class TestOptionalProperty
{
    /**
     * @var integer
     */
    private $id;

    /**
     * @var integer
     */
    private $value;


    /**
     * Get id
     *
     * @return integer 
     */
    public function getId()
    {
        return $this->id;
    }

    /**
     * Set value
     *
     * @param integer $value
     * @return TestOptionalProperty
     */
    public function setValue($value)
    {
        $this->value = $value;

        return $this;
    }

    /**
     * Get value
     *
     * @return integer 
     */
    public function getValue()
    {
        return $this->value;
    }
}

控制器方法：

public function testAction()
{
    $entity = new TestEntity();
    $entity->setName('Testing');
    $entity->setTestOptionalProperty(new TestOptionalProperty());
    $entity->getTestOptionalProperty()->setValue(100);
    $em = $this->getDoctrine()->getManager();
    $em->persist($entity);
    $em->flush();
}

我的学说映射：

AppBundle\Entity\TestEntity:
    type: entity
    table: null
    id:
        id:
            type: integer
            id: true
            generator:
                strategy: AUTO
    fields:
        name:
            type: string
            length: 255
    lifecycleCallbacks: {  }
    manyToMany:
            testOptionalProperty:
                targetEntity: AppBundle\Entity\TestOptionalProperty
                cascade: ["persist"]
                joinTable:
                    name: entity_property
                    joinColumns:
                        entity_id:
                            referencedColumnName: id
                            unique: true
                    inverseJoinColumns:
                        property_id:
                            referencedColumnName: id


AppBundle\Entity\TestOptionalProperty:
    type: entity
    table: null
    id:
        id:
            type: integer
            id: true
            generator:
                strategy: AUTO
    fields:
        value:
            type: integer
    lifecycleCallbacks: {  }

Answer 1

很简单，ArrayCollection __construct只获取Array作为参数，因为您尝试持久化ManyToMany关系，您需要将对象封装在数组中{ {1}}否则会更改$array[] = $object;中实体之间的关系。

顺便说一下，尝试运行OneToOne来生成基于关系的getter和setter

持久化Doctrine关系，Argument 1传递给.. \ ArrayCollection :: __ construct（）必须是类型数组

1 个答案: