Question

我正在创建一个简单的Android应用程序，但是当我运行它时，应用程序停止工作（响应）。我附上了我的申请代码。请帮我。这是MainActivity.java

这是play.java package com.example.guessit;

import java.util.Random;

import android.R.bool;
import android.app.Activity;
import android.app.AlertDialog;
import android.content.DialogInterface;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;

public class Play extends Activity{

EditText et;
Button bt;
int num;
int count = 0;
int min = 1;
int max = 100;

Random r = new Random();
int i1 = r.nextInt(max - min + 1) + min;


@Override
protected void onCreate(Bundle savedInstanceState) {
    // TODO Auto-generated method stub
    super.onCreate(savedInstanceState);
    setContentView(R.layout.game_play);
    et = (EditText) findViewById(R.id.editText1);
    bt = (Button) findViewById(R.id.b1);
    final boolean is_guess = false; 
    num = Integer.parseInt(et.getText().toString());

    bt.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub
             while(is_guess == false) 
             {
              if(num > 100 && num < 0)
              {
            AlertDialog alertDialog = new           AlertDialog.Builder(Play.this).create();
                alertDialog.setTitle("Wrong Input !!");
                alertDialog.setMessage("Please enter the number within the    limit 1 to 100");
                alertDialog.show();
              }
             else if(num > i1)
             {
                Toast.makeText(getApplicationContext(), "Entered number is greater than guessing number", Toast.LENGTH_LONG);
                count++;
             }
             else if(num < i1)
             {
                 Toast.makeText(getApplicationContext(), "Entered number is smaller than guessing number", Toast.LENGTH_LONG);
                    count++;
             }
             else if(num == i1)
             {
                 count++;
                 AlertDialog alertDialog = new AlertDialog.Builder(Play.this).create();
                    alertDialog.setTitle("Congratulations ");
                    alertDialog.setMessage("You Win\n");
                    Log.d("Total", "Attempt = "+count);
                    alertDialog.show();
             }
           }
        }
    });
 }


}

每当我运行这个应用程序时，它运行正常但是当我点击按钮转到play.xml和play.java活动时，它就会运行。但是2或3秒后。它停止了工作。请帮忙。

Answer 1

我认为由于这一行你可能会遇到NumberFormatException：

num = Integer.parseInt(et.getText().toString());

您正在将editText值提取到早期，这样做总是会得到一个无法转换为数字的空字符串。您需要做的是仅在用户输入某个值并单击按钮时从editText获取值。所以只需按照以下代码即可。希望它的帮助！

@Override
protected void onCreate(Bundle savedInstanceState) {
    // TODO Auto-generated method stub
    super.onCreate(savedInstanceState);
    setContentView(R.layout.game_play);
    et = (EditText) findViewById(R.id.editText1);
    bt = (Button) findViewById(R.id.b1);
    final boolean is_guess = false;

    bt.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub

        int num = 0;
        try {
            num = Integer.parseInt(et.getText().toString());
        } catch (NumberFormatException e) {
            num = 0;
            e.printStackTrace();
        }
             while(is_guess == false) 
             {
              if(num > 100 && num < 0)
              {
            AlertDialog alertDialog = new           AlertDialog.Builder(Play.this).create();
                alertDialog.setTitle("Wrong Input !!");
                alertDialog.setMessage("Please enter the number within the    limit 1 to 100");
                alertDialog.show();
              }
             else if(num > i1)
             {
                Toast.makeText(getApplicationContext(), "Entered number is greater than guessing number", Toast.LENGTH_LONG);
                count++;
             }
             else if(num < i1)
             {
                 Toast.makeText(getApplicationContext(), "Entered number is smaller than guessing number", Toast.LENGTH_LONG);
                    count++;
             }
             else if(num == i1)
             {
                 count++;
                 AlertDialog alertDialog = new AlertDialog.Builder(Play.this).create();
                    alertDialog.setTitle("Congratulations ");
                    alertDialog.setMessage("You Win\n");
                    Log.d("Total", "Attempt = "+count);
                    alertDialog.show();
             }
           }
        }
    });
 }

Answer 2

请将logcat添加到您的问题中以帮助您更好，无论如何您在xml中只定义了1 btn并希望在您的活动类中找到3 btn！

play = (Button) findViewById(R.id.button1);
help = (Button) findViewById(R.id.button2);
about = (Button) findViewById(R.id.button3);

在XML中定义button2和button3并查看结果

应用在Android中停止响应

2 个答案: