Question

我有这样的NSString。

0时03分45秒

我想只获得此03:45部分并显示在UILabel

中

我该怎么做？请帮帮我

由于

Answer 1

NSArray *timeParts = [string componentsSeparatedByString: @":"];

NSString *newTime = [NSString stringWithFormat:@"%@/%@", [timeParts objectAtIndex:1], [timeParts objectAtIndex:2]];

Answer 2

不要考虑分割字符串，考虑格式化日期恰好是字符串。你想在这里使用NSDateFormatter。

NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"mm:ss"];
[dateFormatter setTimeZone:[NSTimeZone timeZoneForSecondsFromGMT:0.0]];//Or whatever is applicable for your
NSString *timeString = [self.dateFormatter dateFromString:[NSDate dateFromString:yourString];

或者，如果您真的想从该特定字符串中获取子字符串，则可以执行此操作：

NSString *subString = [yourString substringWithRange:NSMakeRange(3, 7)];

Answer 3

你可以做多种类型的

假设这是你的字符串

NSString *origialString =@"00:03:45";

<强> 1型

NSArray *getBalance = [origialString componentsSeparatedByString: @":"];

origialString = [NSString stringWithFormat:@"%@:%@", [getBalance objectAtIndex:1], [getBalance objectAtIndex:2]];

<强> 2型

origialString = [origialString substringFromIndex:3];

<强>类型-3

origialString = [origialString substringWithRange:NSMakeRange(3, [origialString  length]-3)];

<强>类型4

// Use NSDateformatter but not necessary for here

如何在iOS中拼出NSString

3 个答案: