Question

// My code is doing something; difficult to get.. still a concept can be grasped.
//I am having my method (searchCity) in class graph.   this method is called from main 
//class and is   yes...  selecting one array  by charachter it is passed with 
public class graph {
	int a = 1000;
	int flag = 0;
	//array of all cities having elements as connection to other cities

	public graph(){
		char [] i =  {'i','v'};
		char [] v =  {'v','u'};
		char [] u =  {'u','b','h'};
		char [] b =  {'b','p','f','u'};
		char [] h =  {'h','u','e'};
		char [] e =  {'e','h'};
		char [] p =  {'p','b','r','c'};
		char [] c =  {'c','p'};
		char [] r =  {'r','s','p'};
		char [] s =  {'s','f','r'};
		char [] f =  {'f','s','b'};
	}
	
	public void searchCity( char i, char j){
		// check for equal array as parameter i (include must )
		for (int z = 0 ; z < i.length; z ++) {
		    if (i[z] == 'j') {
	int ascii = (int) 'j';
 int flag = 1; 
	System.out.println(ascii);

		    }
		    else {
		    	// checking for smallest cost in the complete array
		        int ascii = (int) i[z];
		        if(a>ascii)
		        	a=ascii;
		        else continue;
		    }
		}
		if (flag==0){
			char b = (char) a;
			char [] c = {'b'}; 
		}
		searchCity(c, j);
			}

我有一个包含许多数组的类，如char [] a，char [] b等。我在课堂上也有一个方法。在主类中，我创建了一个对象，如果我需要传递两个字母表，它们就像只调用那些名字传递的数组一样。像我在主类中的代码行如下： object.function（char1，char2）; 这些字符将是字母（a，b，c等）可以做到吗？怎么样？？请帮忙。我搜索了它，但确切的问题没有得到解答..问候

Answer 1

如果您询问如何将char数组传递给函数，您需要做的就是按如下方式设置函数：

public static void MyFunction(char[] a, char[] b) {
    //do stuff to char arrays
}

然后，当您调用该函数时，您将能够使用以下命令传递它们：

char[] a = {'a', 'b', 'c'};
char[] b = {'d', 'e', 'f'};
MyObject.MyFunction(a, b);

如果您发布了当前的代码，那将会很有帮助，因此我可以确切地说出您正在尝试做什么。

修改

如果您希望能够使用char调用数组，我建议在HashMap中包含它们：

Map<Character, Character[]> graph = new HashMap<Character, Character[]>(); graph.put('i', new Character[] {'i', 'v'}); graph.put('v', new Character[] {'v', 'u'}); graph.put('u', new Character[] {'u', 'b', 'h'}); // etc.

然后你可以按如下方式调用数组：

System.out.println(graph.get('i')[0]); // Prints 'i' System.out.println(graph.get('i')[1]); // Prints 'v' System.out.println(graph.get('i').length); // Prints '2'

所以函数可能是这样的：

public static void MyFunction(char a, char b) { graph.get(a)[0]; // grab first character in array for (int i=0; i<graph.get(b).length; i++) { // recursively go through array with graph.get(b)[i] } }

Demonstration Here

希望这有帮助。

Answer 2

我发现你的问题有点令人困惑，所以如果我离开了，请告诉我。

但是，我认为你要做的是调用带字符的char数组。例如，使用字符＆＃39; a＆＃39;来调用char数组c。你可以使用if条件的开关来做到这一点。另外，你的object.function（char1，char2）实际上做了什么？那会帮助我回答你的问题。

将数组名称作为类方法中的参数传递

2 个答案: