Question

我在这里写的应用程序设置了一个固定的参考日，在这一天之后我想得到警报！

使用此代码我设置日期和时间：第3天（星期二）和第11小时。这很棒！在viewDidload中使用Timer我的navigationItem.title显示目标日的日/小时/分钟......

现在我将设置一个计时器到这一天/时间，当我在星期二（星期三或星期四）之后打开我的应用程序时，计时器为0并且警报显示！

with：

NSString *currentTimestamp = [NSString stringWithFormat:@"%.f", [resetTime timeIntervalSince1970]];
_epochTimeer.text = currentTimestamp;

我将目标时间转换为我的计时器的纪元时间！

- (void) resetTimer:(id)sender {

        NSDate *today = [NSDate date];
        NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
        [gregorian setLocale:[NSLocale currentLocale]];

        NSDateComponents *nowComponents = [gregorian components:NSYearCalendarUnit | NSWeekCalendarUnit | NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit fromDate:today];

        [nowComponents setWeekday:3]; //2 = Monday 3 di 4 = mi 5 = do 6 = fr 7 = sa
        [nowComponents setWeek: [nowComponents week]+ 1 ]; //Next week [nowComponents week] + 1]
        [nowComponents setHour:11]; //8a.m.
        [nowComponents setMinute:0];
        [nowComponents setSecond:0];

        NSDate *resetTime = [gregorian dateFromComponents:nowComponents];



        NSDateFormatter *df = [[NSDateFormatter alloc] init];
        [df setDateFormat:@"dd-MM-YYYY HH:mm:ss"];
        NSDate *date1 = today;
        NSDate *date2 = resetTime;
        NSTimeInterval interval = [date2 timeIntervalSinceDate:date1];

        int days = (int)interval / 86400;
        int hours = (interval / 3600)-   (days  * 24);
        int minutes =    ((interval / 60) - (days * 24 * 60) -(hours * 60));
        int sekunden = (days * 86400) + (hours * 3600) +(minutes * 60);

        NSString *timeDiff = [NSString stringWithFormat:@"%02d Tage : %02d Std : %02d Min",days, hours, minutes];

        self.navigationItem.title = [NSString stringWithFormat:@"%@",timeDiff];


       NSString *currentTimestamp = [NSString stringWithFormat:@"%.f", [resetTime timeIntervalSince1970]];


        _epochTimeer.text = currentTimestamp;


        NSLog(@"timer: %@",timeDiff);
        NSLog(@"timer: %@",currentTimestamp);
}

如何在此纪元时间或目标日期/时间设置我的计时器？我是计时器和NSDate的初学者，我不明白我怎么能写代码！

或是否有一个完全不同的解决方案，以便在我打开我的APP后的目标日之后获取我的警报！

谢谢Jürgen

抱歉我的英语不好..： - ）

感谢您的帮助，我添加您的代码并将localNotification.fireDate设置为resetTime：

- (void) resetTimer:(id)sender {

        NSDate *today = [NSDate date];
        NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
        [gregorian setLocale:[NSLocale currentLocale]];

        NSDateComponents *nowComponents = [gregorian components:NSYearCalendarUnit | NSWeekCalendarUnit | NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit fromDate:today];

        [nowComponents setWeekday:7]; //2 = Monday 3 di 4 = mi 5 = do 6 = fr 7 = sa
        [nowComponents setWeek: [nowComponents week]]; //Next week [nowComponents week] + 1]
        [nowComponents setHour:9]; //8a.m.
        [nowComponents setMinute:25];
        [nowComponents setSecond:0];

        NSDate *resetTime = [gregorian dateFromComponents:nowComponents];



        NSDateFormatter *df = [[NSDateFormatter alloc] init];
        [df setDateFormat:@"dd-MM-YYYY HH:mm:ss"];
        NSDate *date1 = today;
        NSDate *date2 = resetTime;
        NSTimeInterval interval = [date2 timeIntervalSinceDate:date1];

        int days = (int)interval / 86400;
        int hours = (interval / 3600)-   (days  * 24);
        int minutes =    ((interval / 60) - (days * 24 * 60) -(hours * 60));
        int sekunden = (days * 86400) + (hours * 3600) +(minutes * 60);

        NSString *timeDiff = [NSString stringWithFormat:@"%02d Tage : %02d Std : %02d Min",days, hours, minutes];
       _showTimer.text = [NSString stringWithFormat:@"%02d",sekunden];

        self.navigationItem.title = [NSString stringWithFormat:@"%@",timeDiff];


       NSString *currentTimestamp = [NSString stringWithFormat:@"%.f", [resetTime timeIntervalSince1970]];



        destinationDate = [NSDate dateWithTimeIntervalSince1970:1425981600];


        UILocalNotification *localNotification = [[UILocalNotification alloc] init];
        localNotification.fireDate =resetTime;
        [[UIApplication sharedApplication] scheduleLocalNotification:localNotification];


        NSLog(@"timer: %@",timeDiff);
    NSLog(@"timer: %@",currentTimestamp);

}

这是我的提醒：

-(void)application:(UIApplication *)application didReceiveLocalNotification:(UILocalNotification *)notification
{
        // code to display an alert here

        SCLAlertView *alert = [[SCLAlertView alloc] init];
        alert.backgroundType = Blur;
        UIColor *color = [UIColor colorWithRed:52/255.0 green:222/255.0 blue:192/255.0 alpha:255/255.0];
        [alert showCustom:self image:[UIImage imageNamed:@"geist"] color:color title:NSLocalizedString(@"Auto Reset", nil) subTitle:NSLocalizedString(@"Automatischer Reset Aktiviert!", nil) closeButtonTitle:@"OK" duration:0.0f];


}

当时间到期并且我开始我的应用程序...警报不是，它不会发生..

我需要做的是在某处激活通知吗？

感谢

好的，我现在已经在AppDelegate.m中添加了您的代码

-(void)application:(UIApplication *)application didReceiveLocalNotification:(UILocalNotification *)notification
{

                UIAlertView* alert= [[UIAlertView alloc]initWithTitle:@"My App"
                                                              message:@"Reset"
                                                             delegate:nil
                                                    cancelButtonTitle:@"OK"
                                                    otherButtonTitles:nil];
                [alert show];

        }}

现在它可以工作，当我启动我的应用程序时，警报显示，但它循环闪烁，我不能Klick OK！

现在是什么......？

Answer 1

可以使用NSLocalNotification

来完成

UILocalNotification *localNotification = [[UILocalNotification alloc] init];
 localNotification.fireDate =<target date>;
[[UIApplication sharedApplication] scheduleLocalNotification:localNotification];

-(void)application:(UIApplication *)application didReceiveLocalNotification:(UILocalNotification *)notification
{
// code to display an alert here
}

计时器与目标日显示警报

1 个答案: