显示和搜索日期

时间:2015-03-06 13:57:02

标签: mysql sql

我试图显示发布订单的记录,并让用户搜索customer_name和release_date。

我收到此错误:

  

错误:"您的SQL语法出错;检查手册   对应于您的MySQL服务器版本,以便使用正确的语法   靠近'发布喜欢' %%' '在第19行"    // HTML表单                         //用于搜索的PHP代码       $搜索= $ _ POST ['搜索'];       $搜索1 = $ _ POST ['搜索1'];

$result=mysql_query("SELECT order1.order_id,
                     order1.customer_id,
                     order1.release as releasedate,
                     customer1.customer_name as Customer
                     FROM order1 left join customer1 on order1.customer_id=
                     customer1.customer_id

                     where customer_name LIKE '%$search%'
                     And release Like '%$search1%'
                     order by release Asc") or die(mysql_error());

1 个答案:

答案 0 :(得分:1)

release是mysql保留字,可以看作here

尝试逃避你的查询:

SELECT 
    `order1`.`order_id`,
    `order1`.`customer_id`,
    `order`.`release` AS `releasedate`,
    `customer1`.`customer_name` AS `Customer`
FROM
    `order1`
    LEFT JOIN `customer1` ON `order1`.`customer_id` = `customer1`.`customer_id`
WHERE
    `customer_name` LIKE '%$search%'
    AND `release` LIKE '%$search1%'
ORDER BY
    `release` ASC

为了安全起见,我总是逃避所有的表名和列名。并且使用一种写作风格也是一个好主意 - 在一个你喜欢的代码中,在另一个你喜欢的代码中 - 它将帮助你修改你的代码。