我按照this设置了具有spring security的自定义登录页面。问题是访问/时，它会重定向到/account/login，此/account/login会返回404 Error: NOT_FOUND。如何解决这个问题。
spring-security.xml档案
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.2.xsd">
<http auto-config="true">
<intercept-url pattern="/" access="ROLE_USER" />
<form-login
login-page="/account/login"
default-target-url="/welcome"
authentication-failure-url="/login?error"
username-parameter="email"
password-parameter="password" />
<logout logout-success-url="/login?logout" />
<!-- enable csrf protection -->
<csrf/>
</http>
<beans:bean name="customUserDetailsService" class="com.example.web.CustomUserDetailsService">
</beans:bean>
<authentication-manager>
<authentication-provider user-service-ref="customUserDetailsService">
</authentication-provider>
</authentication-manager>
</beans:beans>
spring-servlet.xml档案
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">
<context:component-scan base-package="com.example.web.*" />
<mvc:annotation-driven />
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp" />
</bean>
</beans>
CustomUserDetailsService档案
public class CustomUserDetailsService implements UserDetailsService {
@Override
public UserDetails loadUserByUsername(String email)
throws UsernameNotFoundException {
if (email == null || email.trim().equals("")) {
throw new UsernameNotFoundException("Invalid email address.");
}
try (Connection conn = Config.getConn()) {
String query = "xxx";
PreparedStatement stm = conn.prepareStatement(query);
stm.setString(1, email);
ResultSet rs = stm.executeQuery();
if (!rs.next()) {
throw new UsernameNotFoundException(
"User does not exist.");
}
if (rs.getBoolean("delete")) {
throw new UsernameNotFoundException("User has been deleted.");
}
Collection<? extends GrantedAuthority> authorities = AuthorityUtils
.createAuthorityList("USER");
String password = rs.getString("pass");
UserDetails user = new User(email, password, true, true, true,
true, authorities);
return user;
} catch (ClassNotFoundException e) {
e.printStackTrace();
} catch (SQLException e) {
e.printStackTrace();
}
throw new UsernameNotFoundException("Unable to connect to database.");
}
}
AccountController档案
@Controller
@RequestMapping("/account")
public class AccountController {
@RequestMapping(value = "/login", method = RequestMethod.GET)
public String Index(Model model) {
return "login";
}
}
HomeController档案
@Controller
@RequestMapping("/")
public class HomeController {
@RequestMapping(value = "/", method = RequestMethod.GET)
public String Index(Model model) {
return "index";
}
}
web.xml档案
<?xml version="1.0" encoding="utf-8" standalone="no"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.5" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<servlet>
<servlet-name>myweb</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>myweb</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring-servlet.xml
</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring-security.xml
</param-value>
</context-param>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<servlet>
<servlet-name>SystemServiceServlet</servlet-name>
<servlet-class>com.google.api.server.spi.SystemServiceServlet</servlet-class>
<init-param>
<param-name>services</param-name>
<param-value>com.example.app.xxx.yyyService</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>SystemServiceServlet</servlet-name>
<url-pattern>/_ah/spi/*</url-pattern>
</servlet-mapping>
<filter>
<filter-name>ObjectifyFilter</filter-name>
<filter-class>com.googlecode.objectify.ObjectifyFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>ObjectifyFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
从谷歌应用引擎
登录ip.ip.ip.ip - - [05 / Mar / 2015：19：41：49 -0800]＆＃34; GET / account / login HTTP / 1.1＆＃34; 404 204 - ＆＃34; Mozilla / 5.0（Macintosh; Intel Mac OS X 10_10_2） AppleWebKit / 537.36（KHTML，与Gecko一样）Chrome / 40.0.2214.115 Safari浏览器/ 537.36＆＃34; ＆＃34; xxx.appspot.com＆＃34; ms = 830 cpu_ms = 606 cpm_usd = 0.000023 instance = 00c61bxxxxxxxxxxxxxxxxxx624e0fc app_engine_release = 1.9.18 trace_id = 60de930xxxxxxxxxxxxxxxxxbb7ab5
修改
问题出在servlet.xml中，将<context:component-scan base-package="com.example.web.*" />更改为<context:component-scan base-package="com.example.web" />并且它可以正常工作。
答案 0 :(得分：0)
首先，确保您可以直接访问登录页面。
在您的web.xml中，查看您为调度员使用的网址格式。这是我的：
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
然后，确保您可以直接请求/login.htm。
登录后，请更改spring-security.xml以附加＆＃34; .htm＆＃34;到您的网址。所以你的片段可能如下所示：
<form-login
login-page="/login.htm"
default-target-url="/welcome.htm"
authentication-failure-url="/login.htm?error"
username-parameter="email"
password-parameter="password" />
<logout logout-success-url="/login.htm?logout" />