Question

我的教授给了我们一个try catch块，他希望我们从现在开始使用所有代码。在阅读完之后，我仍然对如何将其实施到我的程序中感到困惑。

他希望我们在我们的计划中实施的代码。

try {
return 0;
}
catch (exception& e) {
    cerr << "error: " << e.what() << '\n';
    keep_window_open();
    return 1;
}
catch (...) {
    cerr << "Oops: unknown exception!\n";
    keep_window_open();
    return 2;
}

我正在开展的一个项目。

#include "std_lib_facilities_4a.h"
bool yes()
{
string y;
cin >> y;
if (y[0] == 'y' || y[0] == 'Y')
    {
    return true;
    }
else 
    return false;
}
int main()
{
enum {question1=1, question2=2, question3=4};
int result = 0;
cout << " Is what your thinking of red?\n";
if (yes() == true)
    {
    result += question1;
    }
cout << " Is what your thinking of round?\n";
if (yes() == true)
    {
    result += question2;
    }
cout << " Is what your thinking of an animal?\n";
if (yes() == true)
    {
    result += question3;
    }
vector<string> answer = {"You are thinking of a blue square!.","You are thinking of a red square!","you are thing of a blue circle!","You are thinking of a red circle!","you are thinking of a blue animal!","you are thinking of a red animal!","you are thinking of a blue round animal!","You are thinking of a red turtle!"};
cout << answer[result];
return 0;
}

Answer 1

听起来他希望您将代码放在main块try内。然后，如果程序中的任何内容抛出异常而没有其他任何处理它，那么其中一个处理程序将捕获它并干净地结束程序。所以你的main看起来像是

int main() try {
    // your code here
    return 0;   // optional, but polite
} catch (exception& ex) { // better to catch a const reference
    // report it
    return 1;  // should be EXIT_FAILURE for portability
} catch (...)
    // report it
    return 2;  // should also be EXIT_FAILURE
}

没有它们，未被捕获的异常将导致程序通过调用terminate而混乱地结束。在我看来，这样做会更好，因为它往往更容易调试。但是在短期内，做老师所说的话可能会更容易，并且以后会忘掉所有这些坏习惯。

如何使用catch尝试捕获？

1 个答案: