我正在尝试使用具有JSON有效负载的POST请求从REST API获取JSON响应(在发送之前应该转换为URL编码文本)。我已经按照一些教程来实现该过程,但是我收到状态码400的错误。我可能没有编码给定的JSON字符串或遗漏了一些东西。请帮我解决这个问题。感谢。
这是我的代码
try {
URL url = new URL("https://appem.totango.com/api/v1/search/accounts/health_dist");
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setDoOutput(true);
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "application/json");
conn.setRequestProperty("app-token", "1a1c626e8cdca0a80ae61b73ee0a1909941ab3d7mobile+testme@totango.com");
conn.setRequestProperty("Accept", "application/json, text/javascript, */*; q=0.01");
conn.setRequestProperty("X-Requested-With","XMLHttpRequest");
String payload = "{\"terms\":[{\"type\":\"totango_user_scope\",\"is_one_of\":[\"mobile+testme@totango.com\"]}],\"group_fields\":[{\"type\":\"health\"}]}";
OutputStream os = conn.getOutputStream();
os.write(payload.getBytes());
os.flush();
if (conn.getResponseCode() != HttpURLConnection.HTTP_CREATED) {
throw new RuntimeException("Failed : HTTP error code : "
+ conn.getResponseCode());
}
BufferedReader br = new BufferedReader(new InputStreamReader(
(conn.getInputStream())));
String output;
System.out.println("Output from Server .... \n");
while ((output = br.readLine()) != null) {
System.out.println(output);
}
conn.disconnect();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
答案 0 :(得分:0)
在关注了很多帖子和教程超过24小时后,我知道我没有正确发送我的网址参数。我还了解到使用 ApacheHttpClient 进行REST API调用相对容易。我解决了我的HTTP错误代码400并从服务器获得了响应。这是我的问题的工作代码。
try {
httpClient = HttpClients.createDefault();
httpPost = new HttpPost("https://appem.totango.com/api/v1/search/accounts/health_dist");
List<NameValuePair> headers = new ArrayList<NameValuePair>(); //ArrayList to store header parameters
List<NameValuePair> urlParameters = new ArrayList<NameValuePair>(); //ArrayList to store URL parameters
urlParameters.add(new BasicNameValuePair("query","{\"terms\":[{\"type\":\"totango_user_scope\",\"is_one_of\":[\"mobile+testme@totango.com\"]}],\"group_fields\":[{\"type\":\"health\"}]}"));
headers.add(new BasicNameValuePair("app-token", "1a1c626e8cdca0a80ae61b73ee0a1909941ab3d7mobile+testme@totango.com"));
headers.add(new BasicNameValuePair("Accept", "application/json, text/javascript, */*; q=0.01"));
headers.add(new BasicNameValuePair("X-Requested-With", "XMLHttpRequest"));
httpPost.setEntity(new UrlEncodedFormEntity(urlParameters));
for (NameValuePair h : headers)
{
httpPost.addHeader(h.getName(), h.getValue());
}
response = httpClient.execute(httpPost);
if (response.getStatusLine().getStatusCode() != 200) {
throw new RuntimeException("Failed : HTTP error code : "
+ response.getStatusLine().getStatusCode());
}
BufferedReader br = new BufferedReader(new InputStreamReader(
(response.getEntity().getContent())));
String output;
System.out.println("Output from Server .... \n");
while ((output = br.readLine()) != null) {
System.out.println(output);
}
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} finally {
try{
response.close();
httpClient.close();
}catch(Exception ex) {
ex.printStackTrace();
}
}
答案 1 :(得分:-1)
您正在调用的API需要一个名为“query = true | false”的查询参数。
URL url = new URL("https://appem.totango.com/api/v1/search/accounts/health_dist?query=true");
添加此参数后,HTTP请求本身成功,状态代码为200,但REST调用失败并出现服务器端错误。也许你需要一个不同的有效载荷。
我建议如果您是REST新手,请尝试像POSTMan
这样的REST客户端