Question

我正在构建一个twiter web应用程序。它遵循一组选定的推特ID，并且仅根据选择的一组关键字挑选他们发布的推文。一切都工作正常，除了我想将我在数组中的推特ID转换为相应的推特用户名（逐个），例如，ID数组是var trackedHandles;我想将trackedHandles [i]转换为用户名并将其打印到实际推文旁边的控制台。所以它在控制台中看起来像这样：@me：这是我的推文这是我的代码选择与此相关：

t.stream(
    "statuses/filter",
    {track: trackedHandles + trackedWords, lang: "en" },
    function(stream) {
        stream.on('data', function(tweet) {
            for (var i= 0; i < trackedData.length; i++) {
                if(tweet.text.indexOf(trackedData[i]) > - 1) {
                    // incriments added value to the word
                    redisClient.incr(trackedData[i]);

                    console.log(trackedHandles[i] + ":" + " " + tweet.text + " " );
                    //console.log(trackedData[i]);
                }
            }
        }); 
    }
);

现在我只是打印推特ID，但我想再次打印用户名。我感谢您的帮助。

Answer 1

我自己想出来了！如果将来有人需要知道如何：

        //Get Screen_Name from tweet object.
        function getPosition(str,m, i) { //special helper function to find the nth position of a string.
            return str.split(m, i).join(m).length;
        }
        var snStartingPos = getPosition(tweetObject, "screen_name", 2); //starting position of "screen_name" in tweet object.
        var snEndingPos = snStartingPos + 14; //ending position of "screen_name" in tweet object (where we actually want to start).
        var unStartingPos = getPosition(tweetObject, "location", 1); //starting position of the word after where we want to end.
        var unPrePos = unStartingPos - 3; //subtract that by 3 characters to exclude the unnecessary characters
        var snLength = unPrePos - snEndingPos; //this is now the length of the screen_name we want
        var screen_name = "@" + tweetObject.substr(snEndingPos, snLength); //get the sub-str that we want (the "screen_name") from tweet object.
        //End Get Screen_Name from tweet Object

tweetObject只是将推文转换为字符串。函数getPosition，我得到了另一个stackOverflow问题页面：How to get the nth occurrence in a string?

如何将Twitter用户ID转换为Javascript / jQuery中的用户名

1 个答案: