Question

我正在处理SQL查询，该查询计算基于我正在使用的文本字段的重复记录：其中datasource =＆＃39; Web＆＃39;或者＆＃39;内部＆＃39;。我目前正在使用案例陈述来计算记录显示该值的次数。我的问题是如何返回值（我用一个指示符（1或0）来思考一个case语句），它显示了datasource =＆＃39; Web＆＃39;和日期＆gt; datasource =＆＃39;内部＆＃39;和约会？

web.datasource日期＆gt; internal.datasource日期

我附上了一份关于我目前工作的信息，输出信息以及最终结果的查询结果。

SELECT id
,lastname
,firstname
,datasource
,CASE
WHEN (
    (Datasource = 'Web')
    )THEN Count(Datasource)
ELSE 0
    END WebData
,CASE
WHEN (
    (Datasource = 'Internal')
    ) THEN Count(Datasource)
ELSE 0
    END InternalData
,count(id) as countid
,date

FROM Table


GROUP BY
id
,lastname
,firstname
,datasource
,date

目前返回：

12345   Jack    Boss    Internal    0   1   1   2015-03-25
12241   Eric    Graves  Internal    0   1   1   2015-04-01
13300   Su      Lynn    Web         1   0   1   2016-02-01
13300   Su      Lynn    Internal    0   1   1   2015-08-07
13914   Mark    Ross    Internal    0   2   2   2015-05-01
14008   Mitch   Smith   Web         1   0   1   2016-03-07
14008   Mitch   Smith   Internal    0   1   1   2015-06-02

这就是我想要的最终结果：

12345   Jack    Boss    Internal    0   1   1   2015-03-25   0
12241   Eric    Graves  Internal    0   1   1   2015-04-01   0
13300   Su      Lynn    Web         1   0   1   2016-02-01   0
13300   Su      Lynn    Internal    0   1   1   2015-08-07   0
13914   Mark    Ross    Internal    0   2   2   2015-05-01   0
14008   Mitch   Smith   Web         1   0   1   2016-03-07   1
14008   Mitch   Smith   Internal    0   1   1   2015-06-02   1

OR

14008   Mitch   Smith    1   1   2

想法？感谢。

Answer 1

这可能会让你开始：

SELECT id
,lastname
,firstname
,datasource
,CASE
WHEN (
    (Datasource = 'Web')
    )THEN Count(Datasource)
ELSE 0
    END WebData
,CASE
WHEN (
    (Datasource = 'Internal')
    ) THEN Count(Datasource)
ELSE 0
    END InternalData
,count(id) as countid
,date
, sub_table.an_indicator

FROM Table
,   (   select  t2.id as id
,               case when h_table.web_date > h_table.internal_date 
                then 1 
                else 0 end as an_indicator
        from( select t2.id as id
              ,      max( date ) as web_date
              ,      null as internal_date
              from table t2
              where t2.id=Table.id
              and t2.lastname = Table.lastname
              and t2.firstname = Table.firstname
              and t2.datasource = 'Web' 
              group by t2.id
              union
              select t2.id
              ,      null
              ,      max( date ) 
              from table t2
              where t2.id=Table.id
              and t2.lastname = Table.lastname
              and t2.firstname = Table.firstname
              and t2.datasource = 'Internal' 
              group by t2.id
            ) h_table       
    ) sub_table
where sub_table.id = Table.id

Answer 2

select
    id, lastname, firstname, datasource
    case when Datasource = 'Web' then count(Datasource) else 0 end as WebData,
    case when Datasource = 'Internal' then count(Datasource) else 0 end as InternalData,
    count(id) as CountId,
    "date",
    min(dups.flag) as dup
from
    <table> as t
    inner join
    (
        select
            id, lastname, firstname,
            case
                when max(case when datasource = 'web' then "date" end) >
                     max(case when datasource = 'internal' then "date" end)
                then 1 else 0
            end as flag
        from <table>
        group by
            id, lastname, firstname
    ) as dups
        on      dups.id = t.id
            and dups.lastname = t.lastname and dups.firstname = t.firstname
group by
    id, lastname, firstname, datasource

这个可能有用吗？

select
    id, lastname, firstname, datasource
    case when Datasource = 'Web' then count(Datasource) else 0 end as WebData,
    case when Datasource = 'Internal' then count(Datasource) else 0 end as InternalData,
    count(id) as CountId,
    "date",
    case when max(case when datasource = 'web'      then "date" end)
                  over (partition by id, lastname, firstname) >
              max(case when datasource = 'internal' then "date" end)
                  over (partition by id, lastname, firstname)
         then 1
         else 0
    end as dup
from
    <table> as t
group by
    id, lastname, firstname, datasource

SQL：使用案例语句标记重复记录WHERE FIELD VALUE1＆lt;＆gt; FIELD VALUE 2＆amp; FIELD VALUE1 DATE＆gt; FIELD VALUE2

2 个答案: