如果以前曾问过这个问题,我很抱歉,但我找不到类似的东西。
我正在接收CSV输出,该输出使用"
作为每个字段周围的文本限定符。我正在寻找一个优雅的解决方案来重新格式化这些,以便只有特定的(字母数字字段)具有这些限定符。
我收到的一个例子:
"TRI-MOUNTAIN/MOUNTAI","F258273","41016053","A","10/16/14",3,"1","Recruit-Navy,XL#28-75","13.25","13.25"
我想要的输出是这样的:
"TRI-MOUNTAIN/MOUNTAI","F258273",41016053,"A",10/16/14,3,1,"Recruit-Navy,XL#28-75",13.25,13.25
非常感谢任何建议或帮助!
下面的每个请求找到示例文件的前五行:
"TRI-MOUNTAIN/MOUNTAI","F258273","41016053","","10/16/14","","1","Recruit-Navy,XL#28-75","13.25","13.25"
"TRI-MOUNTAIN/MOUNTAI","F258273","41016053","","10/16/14","","1","High Peak-Navy,XL#21-18","36.75","36.75"
"TRI-MOUNTAIN/MOUNTAI","F257186","Z1023384","","10/15/14","","1","Patriot-Red,L#26-35","25.50","25.50"
"TRI-MOUNTAIN/MOUNTAI","F260780","Z1023658","","10/20/14","","1","Exeter-Red/Gray,S#23-52","19.75","19.75"
"TRI-MOUNTAIN/MOUNTAI","F260780","Z1023658","","10/20/14","","1","Exeter-White/Gray,XL#23-56","19.75","19.75"
请注意,这只是一个示例,并非所有文件都适用于Tri-Mountain。
答案 0 :(得分:0)
此问题表示难以将引号与逗号分隔的字段分开,其中字段本身包含嵌入的逗号。 (例如:"Recruit-Navy,XL#28-75"
)有许多方法可以从shell的角度(while read
,awk
等)来解决这个问题。但是大多数方法最终会在嵌入式逗号上发现错误。
发现成功的一种方法是对该线进行蛮力character-by-character
解析。 (下面)这不是一个优雅的解决方案,但它会让你开始。 shell程序的另一种替代方法是编译语言,例如C,其中字符处理更加健壮。如果您有任何疑问,请发表评论。
#!/bin/bash
declare -a arr
declare -i ct=0
## fill array with separated fields (preserving comma in fields)
# Note: the following is a single-line (w/continuations for readability)
arr=( $( line='"TRI-MOUNTAIN/MOUNTAI","F258273","41016053","A","10/16/14",3,"1","Recruit-Navy,XL#28-75","13.25","13.25"'; \
for ((i=0; i < ${#line}; i++)); do \
if test "${line:i:1}" == ',' ; then \
if test "${line:i+1:1}" == '"' -o "${line:i-1:1}" == '"' ; then \
printf " "; \
else \
printf "%c" ${line:i:1}; \
fi; \
else \
printf "%c" ${line:i:1}; \
fi; \
done; \
printf "\n" ) )
## remove quotes from non-numeric fields
for i in "${arr[@]}"; do
if [[ "${i:0:1}" == '"' ]] && [[ ${i:1:1} == [0123456789] ]]; then
arr[$ct]="${i//\"/}"
else
arr[$ct]="$i"
fi
if test "$ct" -eq 0 ; then
printf "%s" "${arr[ct]}"
else
printf ",%s" "${arr[ct]}"
fi
((ct++))
done
printf "\n"
exit 0
<强>输出强>
$ bash sepquoted.sh
"TRI-MOUNTAIN/MOUNTAI","F258273",41016053,"A",10/16/14,3,1,"Recruit-Navy,XL#28-75",13.25,13.25
<强>原始强>
"TRI-MOUNTAIN/MOUNTAI","F258273","41016053","A","10/16/14",3,"1","Recruit-Navy,XL#28-75","13.25","13.25"
答案 1 :(得分:0)
由于您未指定操作系统或语言,因此这是PowerShell版本。
由于你的非标准CSV文件并切换到原始文件处理,我放弃了之前使用Import-CSV
的尝试。也应该明显更快。
要拆分CSV的正则表达式来自这个问题:How to split a string by comma ignoring comma in double quotes
将此脚本另存为StripQuotes.ps1
。它接受以下论点:
[System.Text.Encoding]::GetEncodings()
Write-Verbose
消息告诉您发生了什么。 示例(从PowerShell控制台运行)。
处理文件夹C:\CSVs_are_here
中的所有CSV,将已处理的CSV保存到文件夹C:\Processed_CSVs
,请详细说明:
.\StripQuotes.ps1 -InPath 'C:\CSVs_are_here' -OutPath 'C:\Processed_CSVs' -Verbose
StripQuotes.ps1
脚本:
Param
(
[Parameter(ValueFromPipelineByPropertyName = $true)]
[ValidateScript({
if(!(Test-Path -LiteralPath $_ -PathType Container))
{
throw "Input folder doesn't exist: $_"
}
$true
})]
[ValidateNotNullOrEmpty()]
[string]$InPath = (Get-Location -PSProvider FileSystem).Path,
[Parameter(Mandatory = $true, ValueFromPipelineByPropertyName = $true)]
[ValidateScript({
if(!(Test-Path -LiteralPath $_ -PathType Container))
{
try
{
New-Item -ItemType Directory -Path $_ -Force
}
catch
{
throw "Can't create output folder: $_"
}
}
$true
})]
[ValidateNotNullOrEmpty()]
[string]$OutPath,
[Parameter(ValueFromPipelineByPropertyName = $true)]
[string]$Encoding = 'Default'
)
if($Encoding -eq 'Default')
{
# Set default encoding
$FileEncoding = [System.Text.Encoding]::Default
}
else
{
# Try to set user-specified encoding
try
{
$FileEncoding = [System.Text.Encoding]::GetEncoding($Encoding)
}
catch
{
throw "Not valid encoding: $Encoding"
}
}
$DQuotes = '"'
$Separator = ','
# https://stackoverflow.com/questions/15927291/how-to-split-a-string-by-comma-ignoring-comma-in-double-quotes
$SplitRegex = "$Separator(?=(?:[^$DQuotes]|$DQuotes[^$DQuotes]*$DQuotes)*$)"
# Matches a single code point in the category "letter".
$AlphaNumRegex = '\p{L}'
Write-Verbose "Input folder: $InPath"
Write-Verbose "Output folder: $OutPath"
# Iterate over each CSV file in the $InPath
Get-ChildItem -LiteralPath $InPath -Filter '*.csv' |
ForEach-Object {
Write-Verbose "Current file: $($_.FullName)"
$InFile = New-Object -TypeName System.IO.StreamReader -ArgumentList (
$_.FullName,
$FileEncoding
) -ErrorAction Stop
Write-Verbose 'Created new StreamReader'
$OutFile = New-Object -TypeName System.IO.StreamWriter -ArgumentList (
(Join-Path -Path $OutPath -ChildPath $_.Name),
$false,
$FileEncoding
) -ErrorAction Stop
Write-Verbose 'Created new StreamWriter'
Write-Verbose 'Processing file...'
while(($line = $InFile.ReadLine()) -ne $null)
{
$tmp = $line -split $SplitRegex |
ForEach-Object {
# Strip double quotes, if any
$item = $_.Trim($DQuotes)
if($_ -match $AlphaNumRegex)
{
# If field has at least one letter - wrap in quotes
$DQuotes + $item + $DQuotes
}
else
{
# Else, pass it as is
$item
}
}
# Write line to the new CSV file
$OutFile.WriteLine($tmp -join $Separator)
}
Write-Verbose "Finished processing file: $($_.FullName)"
Write-Verbose "Processed file is saved as: $($OutFile.BaseStream.Name)"
# Close open files and cleanup objects
$OutFile.Flush()
$OutFile.Close()
$OutFile.Dispose()
$InFile.Close()
$InFile.Dispose()
}