Question

我正在尝试使用func1（）和func2（）通过使用计时器来移动圆圈。但它们根本没有移动。那么，如何从两个函数中获取'x'和'x1'值到paintComponent。这是代码：

import java.awt.Graphics;
import java.awt.TextField;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.util.Timer;
import java.util.TimerTask;
import javax.swing.JFrame;
import javax.swing.JPanel;

public class TC extends JPanel
{
    static Timer t1;
    static Timer t2;
    static Timer t3;
    static TimerTask tt1;
    static TimerTask tt2;
    static int x = 0 ,x1 = 500;
    static int y = 100,i = 0,j = 0;
    static Graphics g1;
    static int var = 0;

public static void main(String[] args) throws Exception
{
    TC T = new TC();
    JFrame f = new JFrame("TC");
    f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    JFrame ff = new JFrame("2nd Frame");
    ff.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    TextField tf1 ,tf2;
    f.getContentPane().setLayout(null);
    tf1 = new TextField();
    tf2 = new TextField();  
    tf1.setBounds(50,50, 200, 20);
    tf2.setBounds(50,100, 200, 20);
    f.add(tf1);
    f.add(tf2);
    TC.func1(f,tf1);
    TC.func2(f,tf2);
    ff.add(T);
    ff.setSize(1000, 700);
    ff.setVisible(true);
    f.setSize(1000,700);
    f.setVisible(true);   
}

static void func1(JFrame f,TextField tf1)
{
    //int delay = 100;
    TC T = new TC();
    t1 = new Timer();      
    tt1 = new TimerTask() 
    {
    @Override
    public void run() 
        {              
                    x += 1;
                    y = 100;
                    System.out.println(x);
                    System.out.println(y);
                    tf1.setText(Integer.toString(x));
            if(x1 == x)
            {
                t1.cancel();
                tt1.cancel();
            }             
        };

    };
    t1.scheduleAtFixedRate(tt1,0,50);      
}

static void func2(JFrame f,TextField tf2)
{
    t2 = new Timer();      
    tt2 = new TimerTask() 
    {
    @Override
    public void run() 
        {              
            x1 -= 1;
            y = 100;
            System.out.println(x1);
            System.out.println(y);
            tf2.setText(Integer.toString(x1);
            if(x1 == x)
            {
                t2.cancel();
                tt2.cancel();
            }
        }
    };
    t2.scheduleAtFixedRate(tt2,0,50);
}

    @Override
    public void paint(Graphics g) 
    {
        super.paintComponent(g);
            g1 = g; 
            g.fillOval(x, y, 10, 10);
            g.fillOval(x1, y, 10, 10);
    }            
}

Answer 1

每次移动它时，你可能必须重新绘制圆圈。

将两个圆圈移到一起

1 个答案: