Question

我和我的同学，目前正在学习Java，这是我们的第一个项目。我们必须制作一个骰子游戏，你可以在滚动后获得2个骰子的总和，你必须猜测每个骰子的眼睛。如果他们失败了，他们就会失去他们已经下注的信用额度，并且他们可以选择重新开始，并说出＆＃34; y＆＃34;是的，和＆＃34; n＆＃34;不。如果他们说是，则假设游戏重启，并保留他们当前的信用。我们如何重新启动游戏并保持当前的信用值？

＆＃13;

package dicegame_v1;

import java.util.Scanner;

/**
 *
 * @author williampfaffe
 */
public class Game_engine {

    Player playerTest = new Player();
    int start_credit = 100;
    private static final Scanner s = new Scanner(System.in);

    public Game_engine() {
        /////////////////////////////////////// VI MANGLER TERNINGERNES UDFALD

        String playerName = playerTest.getName();
        System.out.println("Hi, " + playerName + "! Your current balance is " + start_credit + " credit. Please place your bet here:");
        int input = s.nextInt();
        start_credit = start_credit - input;

        if (input > 100) {
            System.out.println("The amount of money you have tried to bet, "
                    + "is larger than your current balance. You only have:" + start_credit
                    + " left on your account");
        } else {

            Dice diceRoll1 = new Dice();
            diceRoll1.rollDice1();
            diceRoll1.getDice1();
            diceRoll1.getDice2();
            System.out.println("The total sum is: " + diceRoll1.diceSum());
            System.out.println("First guess: ");
            int input_dice1 = s.nextInt();
            System.out.println("Second guess: ");
            int input_dice2 = s.nextInt();
            if (input_dice1 == diceRoll1.getDice1() && input_dice2 == diceRoll1.getDice2()) {
                start_credit = (input * 2) + start_credit;
                System.out.println("You're correct! You have won: " + input + ". Your current balance is now: " + (start_credit));
                System.out.println("Do you want to continue playing? Yes: y No: n");
                String keep_playing = s.nextLine();
                if (keep_playing.equals("y")) {

                    System.out.println("");
                } else {
                    System.out.println("Hope to see you again!");
                }

            } else {

                System.out.println("You're incorrect! You have lost your money! Your current balance is: " + (start_credit));
                
                System.out.println("Do you want to continue playing? Yes: y No: n");
                String keep_playing = s.nextLine();
                if (keep_playing.equals("n")) {

                    System.out.println("Hope to see you again!");
                } else {
                    System.out.println("");
                }

            }

        }

    }
}

＆＃13;

Answer 1

将if / else包装在一个循环中，如：

 while (true) {
   ...
   if (keep_playing.equals("y")) {//you may want to use equalsIgnoreCase api to do case insensitive match for y ?
        continue;
   } else {
       System.out.println("Hope to see you again!");
       break;
   }
 }

Answer 2

您将其封装在while循环中，该循环检查转义条件：

boolean game = true;

while(game) {

    //Do your stuff         

    if(keep_playing.equals("n")) {
      game = false;
    }
}

重新启动骰子游戏，如果输入是肯定的？

2 个答案: