Question

我正在连接到web服务，即android中的service.asmx。我能够连接到服务并获得共鸣但我得到的响应如下。服务器发送给我一个有效的xml但我无法正确读取xml。我得到的输出如下

anyType{schema=anyType{element=anyType{complexType=anyType{choice=anyType{element=anyType{complexType=anyType{sequence=anyType{element=anyType{}; element=anyType{}; element=anyType{}; element=anyType{}; element=anyType{}; }; }; }; }; }; }; }; diffgram=anyType{}; }

并且用于获得响应的代码如下所示。envelope.getResponse是否会返回xml格式，或者我需要使用其他东西。我已经搜索了但是我仍然不清楚这个。

HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
        SoapEnvelope.VER11);
SoapObject request = new SoapObject(NAMESPACE, MethName);
envelope.setOutputSoapObject(request);
androidHttpTransport.debug=true;

// Property which holds input parameters
PropertyInfo sayHelloPI = new PropertyInfo();
// Set Name
sayHelloPI.setName("UserId");
// Set Value
sayHelloPI.setValue(1);
// Set dataType
sayHelloPI.setType(int.class);
// Add the property to request object
request.addProperty(sayHelloPI);
//Set envelope as dotNet
envelope.dotNet = true;

try {

    // Invoke web service
    androidHttpTransport.call(SOAP_ACTION, envelope);

    // Get the response
  SoapObject response = (SoapObject) envelope.getResponse();
  System.out.println("response-----------------"+response);

Answer 1

谢谢大家，我使用了这种方法

String ss=httpTransport.responseDump;

它给了我一个有效格式的xml

无法从Web服务读取有效的xml

1 个答案: