Question

我有一个仓库Fact Table，其中包含通过数据Feed从供应商处收到的原始数据（甚至是重复数据）。我需要准备15 Min Interval数据块。我怎样才能最好的SQL Server查询来做到这一点。例如。样本数据

ID key Date                              Value
1  1    2013-10-08 00:00:00.000       10 
2  1    2013-10-08 00:23:00.000       15 
3  1    2013-10-08 01:00:00.000       20    
4  1    2013-10-08 01:15:00.000       25 
5  1    2013-10-08 01:30:00.000       30 
6  1    2013-10-08 01:35:00.000       30 
7  1    2013-10-08 01:50:00.000       30 
8  1    2013-10-08 01:55:00.000       30

Answer 1

通过构建一个指定每批次开始的新列，以每小时的固定批次进行批处理：

SELECT
    *,
    CASE
        WHEN (DATEPART(minute, [Date]) >= 0 AND DATEPART(minute, [Date]) < 15) THEN DATETIMEFROMPARTS (DATEPART(year, [Date]), DATEPART(month, [Date]), DATEPART(day, [Date]), DATEPART(hour, [Date]), 0, 0, 0)
        WHEN (DATEPART(minute, [Date]) >= 15 AND DATEPART(minute, [Date]) < 30) THEN DATETIMEFROMPARTS (DATEPART(year, [Date]), DATEPART(month, [Date]), DATEPART(day, [Date]), DATEPART(hour, [Date]), 15, 0, 0)
        WHEN (DATEPART(minute, [Date]) >= 30 AND DATEPART(minute, [Date]) < 45) THEN DATETIMEFROMPARTS (DATEPART(year, [Date]), DATEPART(month, [Date]), DATEPART(day, [Date]), DATEPART(hour, [Date]), 30, 0, 0)
        ELSE DATETIMEFROMPARTS (DATEPART(year, [Date]), DATEPART(month, [Date]), DATEPART(day, [Date]), DATEPART(hour, [Date]), 45, 0, 0)
    END AS BatchStart
FROM
    Fact
ORDER BY
    [Date]

您的示例的结果：

ID  key  Date                     Value  BatchStart
1   1    2013-10-08 00:00:00.000  10     2013-10-08 00:00:00.000
2   1    2013-10-08 00:23:00.000  15     2013-10-08 00:15:00.000
3   1    2013-10-08 01:00:00.000  20     2013-10-08 01:00:00.000
4   1    2013-10-08 01:15:00.000  25     2013-10-08 01:15:00.000
5   1    2013-10-08 01:30:00.000  30     2013-10-08 01:30:00.000
6   1    2013-10-08 01:35:00.000  30     2013-10-08 01:30:00.000
7   1    2013-10-08 01:50:00.000  30     2013-10-08 01:45:00.000
8   1    2013-10-08 01:55:00.000  30     2013-10-08 01:45:00.000

Answer 2

这将向下舍入到最近的15分钟

SELECT dateadd(minute, datediff(minute, 0, Date)/15*15, 0) 
FROM yourtable

TSQL准备15 Min Chunk Data

2 个答案: