Question

我想废弃这个滚动网站的内容： http://stocktwits.com/symbol/AAPL?q=AAPL

我在Stactoverflow中找到了类似问题的答案： scrape websites with infinite scrolling

以下是从那里复制的代码：

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import Select
from selenium.webdriver.support.ui import WebDriverWait
from selenium.common.exceptions import TimeoutException
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import NoSuchElementException
from selenium.common.exceptions import NoAlertPresentException
import sys

import unittest, time, re

class Sel(unittest.TestCase):
    def setUp(self):
        self.driver = webdriver.Firefox()
        self.driver.implicitly_wait(30)
        self.base_url = "https://twitter.com"
        self.verificationErrors = []
        self.accept_next_alert = True
    def test_sel(self):
        driver = self.driver
        delay = 3
        driver.get(self.base_url + "/search?q=stckoverflow&src=typd")
        driver.find_element_by_link_text("All").click()
        for i in range(1,100):
            self.driver.execute_script("window.scrollTo(0, document.body.scrollHeight);")
            time.sleep(4)
        html_source = driver.page_source
        data = html_source.encode('utf-8')


if __name__ == "__main__":
    unittest.main()

现在取代推特，我想废弃Stocktwits网站（链接在上面）。

我将上面的代码修改为：

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import Select
from selenium.webdriver.support.ui import WebDriverWait
from selenium.common.exceptions import TimeoutException
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import NoSuchElementException
from selenium.common.exceptions import NoAlertPresentException
import sys

import unittest, time, re

class Sel(unittest.TestCase):
    def setUp(self):
        self.driver = webdriver.Firefox()
        self.driver.implicitly_wait(30)
        self.base_url = "http://stocktwits.com/symbol/AAPL?q=AAPL"
        self.verificationErrors = []
        self.accept_next_alert = True
    def test_sel(self):
        driver = self.driver
        delay = 3
        driver.get(self.base_url)
        driver.find_element_by_link_text("All").click()
        for i in range(1,100):
            self.driver.execute_script("window.scrollTo(0, document.body.scrollHeight);")
            time.sleep(4)
        html_source = driver.page_source
        data = html_source.encode('utf-8')


if __name__ == "__main__":
    unittest.main()

但是当我运行代码时，我收到了这个错误：

NoSuchElementException: Message: Unable to locate element: {"method":"link text","selector":"All"}

我感谢任何帮助，以找出问题所在。

Answer 1

看起来问题在于这一行：

driver.find_element_by_link_text("All").click()

您期望一个链接文字为"All"的元素，但不存在。

使用Selenium在Python中搜索无限滚动网站

1 个答案: