Question

问题：在我的代码中我想删除标题tr html标记（女巫属性为<tr class='background1'>）

urL http://www.rayansaba.com/index.php?ukey=pricelist

在下面的代码中，如果条件要避免标题，但我不能删除。

$table_rows = $xpath->query("//div[@class='cpt_maincontent']/center/table/tr"); // target the row (the browser rendered <tbody>, but actually it really doesnt have one)

if($table_rows->length <= 0) { // exit if not found
    echo 'no table rows found';
    exit;
}
 $i = 0;
 $trlength = count($table_rows);

foreach($table_rows as $tr){
$row = $tr->childNodes;
   if($row->item(0)->tagName!='<tr class="background1"></tr>') { // avoid headers
        $data[] = array(
            'Name' => trim($row->item(0)->nodeValue),
            'Price' => trim($row->item(2)->nodeValue),





        );

    }

    }

Answer 1

实际上，您可以在xpath查询中添加它，排除那些带背景的行，然后提取值并相应地推送节点值。例如：

$dom = new DOMDocument;
@$dom->loadHTMLFile('http://www.rayansaba.com/index.php?ukey=pricelist');
$xpath = new DOMXpath($dom);
$table_rows = $xpath->query("//div[@class='cpt_maincontent']/center/table/tr[not(@class)]");
$data = array();
foreach($table_rows as $tr) {
    if($tr->getElementsByTagName('td')->length > 2) {
        $name = trim($tr->getElementsByTagName('td')->item(0)->nodeValue);
        $price = trim($tr->getElementsByTagName('td')->item(2)->nodeValue);
        $data[] = array('Name' => $name, 'Price' => $price);
    }

}
echo '<pre>', print_r($data, 1), '</pre>';

删除一个或多个标签xpath php

1 个答案: