Question

我无法使用hibernate创建临时表这里是我的代码

        getSession().beginTransaction();
        String queryString1 = "CREATE TEMPORARY TABLE  sage_temp_table(CRMID VARCHAR(60),POPAmountPaid DECIMAL(14,2)) ";
        getSession().createSQLQuery(queryString1).executeUpdate();
        getSession().flush();
        String queryString2 = "INSERT INTO sage_temp_table(CRMID,POPAmountPaid) SELECT  CRMID,POPAmountPaid FROM sage_payments WHERE sage_payments.`CRMID` REGEXP \"^[0-9]+$\" AND"
                + " sage_payments.POPPaidDate NOT LIKE \"%0000-00-00 00%\" AND sage_payments.POPPaidDate IS NOT NULL AND sage_payments.POPAmountPaid IS NOT NULL";
        getSession().createSQLQuery(queryString2).executeUpdate();
        getSession().beginTransaction().commit();

在日志中它显示命令正在运行，但是当我从表中选择内容时，它表示表sage_temp_table不存在因此不会创建并且不会给出任何错误。这是日志

  04:00:04,549 INFO  [STDOUT] Hibernate: CREATE TEMPORARY  TABLE  sage_temp_table(CRMID VARCHAR(60),POPAmountPaid DECIMAL(14,2)) 
  04:00:17,463 INFO  [STDOUT] Hibernate: INSERT INTO sage_temp_table(CRMID,POPAmountPaid) SELECT  CRMID,POPAmountPaid FROM sage_payments WHERE sage_payments.`CRMID` REGEXP "^[0-9]+$" AND        sage_payments.POPPaidDate NOT LIKE "%0000-00-00 00%" AND          sage_payments.POPPaidDate IS NOT NULL AND sage_payments.POPAmountPaid IS NOT NULL

此处还有一个案例，当我从queryString1表中删除TEMPORARY时，会创建并插入。请告诉我它有什么问题？

无法使用Hibernate创建临时表

0 个答案: