在这种情况下，如何获得外部f​​oreach循环值？

Question

我试图从mysql数据中调用foreach循环中的所有值，并将值输入用于另一个mysql select语句。看下面的代码。它只能收集一个值。我想使用第一个foreach循环包括整个部分，但是，因为foreach值是个体的，我需要爆炸数组为PDO准备。所以，最后，我想知道一种从外部foreach循环中获取所有值的方法。升值。

//mysql connection code, remove because it is not relative to this question
foreach ($tag_id as $term){
	$term=$term['term'].' ';//use space to seprate each one
   
 }
	echo $term:// only can can one, how can I get all result from above foreach.
	$term=explode(' ', $term);
	
	
	$stm =$db->prepare("SELECT user_id FROM sign WHERE term IN (:term_0,:term_1,:ts.id, s.term, s.counter, os.user_id, os.id, COUNT(oserm_2,:term_3,:term_4,:term_5,:term_6,:term_7,:term_8,:term_9,:term_10)");

$term_0="$term[0]";
	$term_1="$term[1]";
	$term_2="$term[2]";
	$term_3="$term[3]";
	$term_4="$term[4]";
//following code is not relevive to this question.

Answer 1

如果你最后的目的是从你的值创建数组，为什么要将数据附加到字符串，只需将数据添加到数组然后直接使用它。

foreach ($tag_id as $term){
    $term_arr[]=$term['term'];

 }

 print_r($term_arr);

然后你可以使用

   $stm =$db->prepare("SELECT user_id FROM sign WHERE term IN (:term_0,:term_1,:ts.id, s.term, s.counter, os.user_id, os.id, COUNT(oserm_2,:term_3,:term_4,:term_5,:term_6,:term_7,:term_8,:term_9,:term_10)");

$term_0="$term_arr[0]";
    $term_1="$term_arr[1]";
    $term_2="$term_arr[2]";
    $term_3="$term_arr[3]";
    $term_4="$term_arr[4]";

Answer 2

假设$ tag_id是mysql查询的数组输出

$t = array();
foreach ($tag_id as $term){
    $t[]=$term['term']; // create array of terms 
 }
$str = "'".implode("','",$t)."'"; // make it a string, you can add here any other string you want to complete your query
    $stm =$db->prepare("SELECT `user_id` FROM `sign` WHERE `term` IN (".$str.");
$stm =$db->execute(); 

Answer 3

每次你创建循环时，你都会覆盖vale os $ term，请看：

      $string = ''

        foreach ($tag_id as $term){
            $string .= $term['term'] . ' ';//use space to seprate each one

         }

         $term = $string;
   echo $term:// only can can one, how can I get all result from above foreach.
    $term=explode(' ', $term);


    $stm =$db->prepare("SELECT user_id FROM sign WHERE term IN (:term_0,:term_1,:ts.id, s.term, s.counter, os.user_id, os.id, COUNT(oserm_2,:term_3,:term_4,:term_5,:term_6,:term_7,:term_8,:term_9,:term_10)");

$term_0="$term[0]";
    $term_1="$term[1]";
    $term_2="$term[2]";
    $term_3="$term[3]";
    $term_4="$term[4]";
//following code is not relevive to this question.

其他循环：

  $string = array();

    foreach ($tag_id as $term){
        $string[] = $term['term'];
     }

$term = $string;