Question

考虑这个例子：

import textwrap
import pprint

mystr=r"""
First line.
Second line.
The third line is a very long line, which I would like to somehow wrap; wrap at 80 characters - or less, or more! ... can it really be done ??"""

pprint.pprint(textwrap.wrap(mystr,80))

字符串mystr已经是一个多行字符串，因为它包含换行符;但是，如果我运行这个脚本，我得到输出：

[' First line. Second line. The third line is a very long line, which I would like',
 'to somehow wrap; wrap at 80 characters - or less, or more! ... can it really be',
 'done ??']

...这意味着textwrap.wrap首先加入＆＃34;多行字符串（即删除其中的现有换行符），然后将其包装（即将其拆分为给定的字符数）。

如何换行多行字符串，以便保留换行符？也就是说，在这种情况下，预期的输出将是：

['First line.', 
 'Second line.', 
 'The third line is a very long line, which I would like to somehow wrap; wrap at',
 '80 characters - or less, or more! ... can it really be done ??']

EDIT;感谢@u_mulder的评论，我试过了：

textwrap.wrap(mystr,80,replace_whitespace=False)

然后我得到：

['\nFirst line.\nSecond line.\nThe third line is a very long line, which I would like',
 'to somehow wrap; wrap at 80 characters - or less, or more! ... can it really be',
 'done ??']

换行符似乎被保留了，但是＆＃34; inline＆＃34;字符;所以这里第一个元素本身就是一个多行字符串 - 所以它不是我需要它，每一行都是一个数组元素。

Answer 1

分割后只需添加新行：

import textwrap
import pprint
import itertools

mystr=r"""
First line.
Second line.
The third line is a very long line, which I would like to somehow wrap; wrap at 80 characters - or less, or more! ... can it really be done ??"""

wrapper = textwrap.TextWrapper(width = 80)
mylist = [wrapper.wrap(i) for i in mystr.split('\n') if i != '']
mylist = list(itertools.chain.from_iterable(mylist))

pprint.pprint(mylist)

输出：

['First line.',
 'Second line.',
 'The third line is a very long line, which I would like to somehow wrap; wrap at',
 '80 characters - or less, or more! ... can it really be done ??']

Answer 2

好吧，我想我找到了如何做我想做的事，但它有点不优雅：

import textwrap
import pprint

mystr=r"""
First line.
Second line.
The third line is a very long line, which I would like to somehow wrap; wrap at 80 characters - or less, or more! ... can it really be done ??"""

#pprint.pprint(textwrap.wrap(mystr,80,replace_whitespace=False))

aa=[]
for ix in mystr.splitlines():
  if ix:
    if len(ix)<=80: aa.append(ix)
    else: aa.extend(textwrap.wrap(ix,80))

pprint.pprint(aa)

结果如下：

['First line.',
 'Second line.',
 'The third line is a very long line, which I would like to somehow wrap; wrap at',
 '80 characters - or less, or more! ... can it really be done ??']

所以：

1st elem：＆＃39;第一行。＆＃39;最初定义
第二个元素：＆＃39;第二行。＆＃39;这也是最初定义的
第3个元素：原来的第三行太长了，所以它被包装成80个字符，第一部分是数组中的第3个元素
4th elem：包含原始第三行的第二部分

这就是我想要实现的目标;请注意，这与数组中的第一个元素包含多行时的情况完全不同，如['\nFirst line.\nSecond line.\nThe third line ...中所示。

在Python中包装多行字符串（保留现有的换行符）？

2 个答案: