我有以下代码来获取查询结果。查询结果采用JSON格式。
$.ajax({
url: ..... //url//...,
contentType: "application/json; charset=utf-8",
data: JSON.stringify({
"type": "daysofyear",
"entity": {
"year": "2015"
}
}),
type: "POST",
dataType: "json",
success: function(result) {
if ((result) && (result.isSuccess == true)) {
alert("SUCCESS");
alert(json.entity.day);
}
},
});
返回的JSON是:
{
"isSuccess": true,
"results": [{
"jsonClass": "RuleSuccess",
"message": "Found mapping for year: 2015",
"rule": {
"name": "Year rule",
"metadata": {}
},
"entity": {
"year": "2015",
"month": "December",
"day": "Saturday"
}
}]
}
我基本上试图分别提取月,年,日的值,并使用
单独显示它们alert(json.entity.day);
请建议。
答案 0 :(得分:3)
<强>更新强>
var a =JSON.parse('{"isSuccess":true,"results":[{"jsonClass":"RuleSuccess","message":"Found mapping for year: 2015","rule": {"name":"Year rule","metadata":{}}, "entity":{"year":"2015", "month":"December", "day":"Saturday"}}]}') ;
alert(a.results[0].entity.day);
<强>原始强>
使用
alert(result[0].rule.entity.day);
答案 1 :(得分:0)
试试这个:
obj = JSON.parse(json);
console.log(obj[0].rule.entity.day);