假设我有一个类似于这种格式的文件:
"pop","hand stuff","test "
"non","no way","good "
除了只有3列它有数百个。我想在每列的末尾添加@,因此输出为
"pop@","hand stuff@","test @"
"non@","no way@","good @"
如果我只有少量列,那么我可以做
awk -F"," vOFS=, '{print $1"@",$2"@",$3"@"}'
但如果我有很多列并且我不想在awk脚本中指定每一列,我该如何做?
答案 0 :(得分:1)
你可以使用像下面这样的awk&#39s gsub函数。
awk '{gsub(/",/, "@\",");sub(/"$/, "@\"")}1' file
示例:
$ echo '"pop","hand stuff","test "' | awk '{gsub(/",/, "@\",");sub(/"$/, "@\"")}1'
"pop@","hand stuff@","test @"
答案 1 :(得分:1)
只要您的专栏不包含疯狂数据(特别是字符串中嵌入\",
),sed就会更容易:
OSX / BSD:
sed -E 's/"(,|$)/@"\1/g'
GNU:
sed -r 's/"(,|$)/@"\1/g'
答案 2 :(得分:1)
$ sed -r 's/("[^"]+)"/\1@"/g' file
"pop@","hand stuff@","test @"
"non@","no way@","good @"