我正在使用 Python 2.6 , ElementTree 和 SQLite3 。我的脚本目前执行以下操作:
以下是我一直在检索架构数据并向XML添加元素的方法。我使用SOFTWARE_
和TARGET_
表执行此操作。这是针对SOFTWARE_
表:
software_attributes = ["id", "functionalDesignationHardware", "hwfin", "identname", "partnumber",
"repfin", "targetHardwareID"]
software = db.cursor().execute("SELECT %s from SOFTWARE_" % ", ".join([i + "_" for i in software_attributes]))
software_Data = software.fetchall()
ID1 = db.cursor().execute("SELECT id_ from SOFTWARE_")
software_IDs = ID1.fetchall()
for sw in software_Data:
sw_node = ET.SubElement(root, "Software")
for s in range(1, len(software_attributes)):
sw_node.set(software_attributes[s], str(sw[s]))
更新:这是我TARGET_
表的代码:
target_attributes = ["id", "functionalDesignationSoftware", "installscriptpathname", "ata", "status",
"swfin", "targetOSFC", "timestamp"]
target = db.cursor().execute("SELECT %s from TARGET_" % ", ".join([i + "_" for i in target_attributes]))
target_Data = target.fetchall()
ID2 = db.cursor().execute("SELECT id_ from TARGET_")
target_IDs = ID2.fetchall()
## CURRENTLY INCORRECT - only adds to the last created Software Element ##
for tg in target_Data:
tg_node = ET.SubElement(sw_node, "TargetModule")
for t in range(1, len(target_attributes)):
tg_node.set(target_attributes[t], str(tg[t]))
这就是我存储来自表的信息的方式,这些表的唯一目的是连接来自其他表的数据。 SOFTWARE_TARGET_
表格将SOFTWARE_
与TARGET_
相关联。我将其信息存储在字典中:
software_target = db.cursor().execute("SELECT SOFTWARE1, TARGET2 from SOFTWARE_TARGET_")
software_target_Data = software_target.fetchall()
# Map SOFTWARE1 to TARGET2
separated_st_Data = {}
for item in software_target_Data:
software1, target2 = item
try:
separated_st_Data[software1].append(target2)
except KeyError:
separated_st_Data[software1] = [target2]
到目前为止,我已经找到了如何以下列格式设置我的xml:
<Software attribute="stuff" attribute2="Stuff"/>
<Software attribute="stuff" attribute2="Stuff"/>
<Target attribute="things" attribute2="Things"/>
但我需要的是以下格式:
<Software attribute="stuff" attribute2="Stuff"
<Target attribute="things" attribute2="Things"/>
<Target attribute="things" attribute2="Things"/>
</Software>
<Software attribute="stuff" attribute2="Stuff"/>
Target
个子元素位于哪个Software
元素由SOFTWARE_TARGET_
表中的信息确定。我已经找到了如何遍历我的字典,如下:
depth=0
for k,v in sorted(separated_st_Data.items(),key=lambda x: x[0]):
if isinstance(v, dict):
print (" ")*depth + ("%s" % k)
walk_dict(v,depth+1)
else:
print (" ")*depth + "%s %s" % (k, v)
如何根据数据库表中的信息创建格式正确的XML文件(如 Attemps 部分所述)?我创建了字典,以为我可以将它用于此目的 - 如果有必要,请告诉我。
备注
This是我从SOFTWARE_TARGET_
表创建的字典的样子。键代表id_
中的SOFTWARE_
架构,值代表id_
中的TARGET_
架构。 (请告诉我,如果我的术语听起来有点 - 数据库有时让我困惑)。
答案 0 :(得分:1)
创建Target
元素时(此处未在问题中提供代码),请务必将他们想要附加的sw_node
作为第一个参数传递。
那是:
target_el = SubElement(sw_node, "Target")
而不是......
target_el = SubElement(root_node, "Target")
此类代码的典型模式可能具有以下外观(粗略;需要一些测试,使用pyformat
参数样式为DB-API驱动程序编写,并且不与其他人一起工作):< / p>
cursor = db.cursor()
cursor.execute("SELECT * from SOFTWARE_")
for sw_item in cursor.fetchall():
sw_el = SubElement(root_el, 'Software') ## STORING THE ELEMENT HERE
sw_id = None
for idx in range(len(cursor.description)):
name = cursor.description[idx][0]
if name == 'id':
sw_id = sw_item[idx]
sw_el.attrib[name] = sw_item[idx]
## QUERYING FOR CHILDREN HERE
cursor.execute("SELECT TARGET_.*
FROM TARGET_, SOFTWARE_TARGET_
WHERE SOFTWARE_TARGET_.SOFTWARE1=%(sw_id)s
AND SOFTWARE_TARGET_.TARGET2=TARGET_.ID",
sw_id=sw_id)
for target_item in cursor.fetchall():
# create a new target element
target_el = SubElement(sw_el, 'Target')
# assign attributes to that element
for idx in range(len(cursor.description)):
name = cursor.description[idx][0].rsplit('.', 1)[-1]
target_el.attrib[name] = target_item[idx]
答案 1 :(得分:0)
哎呀,差点忘了 - 这是最终代码我最终在完成的Python脚本中使用(当然,减去完整脚本的几个关键元素):
software_attributes = ["id", "partnumber", "identname", "functionalDesignationHardware", "hwfin",
"targetHardwareID","repfin", "amendment"]
target_attributes = ["id", "swfin", "targetOSFC", "functionalDesignationSoftware", "installscriptpathname",
"ata", "status","timestamp"]
sw_current = cursor.execute("SELECT %s from SOFTWARE_" % ", ".join([i + "_" for i in software_attributes]))
sw_current = sw_current.fetchall()
for sw_item in sw_current:
current_sw_ID = sw_item[0]
# Create Software XML Element
sw_element = ET.SubElement(root, "Software")
# Set Software attributes
for s in range(1, len(software_attributes)):
sw_element.set(software_attributes[s], str(sw_item[s]))
# Get all Target IDs for current Software Element
current_tg_IDs = cursor.execute("SELECT TARGET2 from SOFTWARE_TARGET_ WHERE SOFTWARE1=?", (current_sw_ID,))
current_tg_IDs = list(chain.from_iterable(current_tg_IDs.fetchall()))
while len(current_tg_IDs) > 0:
tg_id = current_tg_IDs.pop(0)
tg_current = cursor.execute("SELECT %s from TARGET_ WHERE id_=?" % ", ".join([i + "_" for i in target_attributes]), (str(tg_id).strip('[]'),))
tg_current = tg_current.fetchall()
for tg_item in tg_current:
# Create Target XML Element
tg_element = ET.SubElement(sw_element, "TargetModule")
# Set Target attributes
for t in range(1, len(target_attributes)):
tg_element.set(target_attributes[t], str(tg_item[t]))
注意:在上面的最后一次尝试中,我最终没有使用最初在此问题中假设的字典方法 - 我的最终方法对我的目的更有效。有关使用词典的方法示例,请参阅此问题的选定答案。