Question

如何将计算字段添加到实体？

数据库表

table person {
    id number,
    first_name varchar,
    last_name varchar,
    ...
}

Java实体

public class person {
    BigDecimal id;
    String firstName;
    String lastName;
...//getters and setters

    //what to add here???
    public String getFullName() {
        return firstName + " " + lastname;
    }
}

我尝试添加@Transient，但转换为json时会忽略该字段。我尝试将方法留在那里，抛出了一个异常，即setter丢失了。添加setter会引发另一个异常，即该字段在DB中不存在。我尝试添加@Transient和@JsonPropert，但转换为json时会忽略该字段。我尝试添加@Formula，但是hibernate（我认为）说它没有实现。

这个想法是让一个简单的计算字段被jpa / hibernate忽略，但是被jackson使用。我怎么能做到这一点？

修改

示例全班

@Entity
@Table(name="FDF_PATIENT_COUNTIE")
@JsonIdentityInfo(generator = JSOGGenerator.class)
@JsonIgnoreProperties(ignoreUnknown = true)
@Audited
public class PatientCounty extends FgaBaseClass {

    private static final long serialVersionUID = 1425318521043179798L;

    private BigDecimal id;
    private County FCounties;
    private Patient patients;

    public PatientCounty() {
    }

    public PatientCounty(County FCounties, Patient patients) {
        this.FCounties = FCounties;
        this.patients = patients;
    }

    @SequenceGenerator(name="generator", sequenceName="FDF_PATIENT_COUNTIE_SEQ")
    @Id
    @GeneratedValue(strategy=SEQUENCE, generator="generator")
    @Column(name="ID", unique=true, nullable=false, precision=22, scale=0)
    public BigDecimal getId() {
        return this.id;
    }

    public void setId(BigDecimal id) {
        this.id = id;
    }

    @ManyToOne(fetch=FetchType.LAZY)
    @JoinColumn(name="ID_F_COUNTIE")
    public County getFCounties() {
        return this.FCounties;
    }

    public void setFCounties(County FCounties) {
        this.FCounties = FCounties;
    }

    @ManyToOne(fetch=FetchType.LAZY)
    @JoinColumn(name="ID_FDF_PATIENT")
    public Patient getPatients() {
        return this.patients;
    }

    public void setPatients(Patient patients) {
        this.patients = patients;
    }
}

在jpa + jackson上添加计算字段

0 个答案: