Question

您好！

正如标题中所述，我试图将我的视图解析器配置从经典xml导出到java conf。（我不认为我会因为这个选择而进入......？）

我之前的说法是：

的web.xml：

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/dispatcher-servlet.xml</param-value>
</context-param>
...
<servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
</servlet>

dispatcher-servlet.xml：

<context:component-scan base-package="ca.mat8j8.controller" />

<!-- freemarker config -->
<bean class="org.springframework.web.servlet.view.freemarker.FreeMarkerConfigurer">
    <property name="templateLoaderPath" value="/WEB-INF/views/"/>
</bean>

<!--
View resolvers can also be configured with ResourceBundles or XML files. If you need
different view resolving based on Locale, you have to use the resource bundle resolver.
-->
<bean class="org.springframework.web.servlet.view.freemarker.FreeMarkerViewResolver">
    <property name="cache" value="true"/>
    <property name="prefix" value=""/>
    <property name="suffix" value=".ftl"/>
</bean>

这样，它没有问题。

现在我尝试摆脱我的xml conf：

web.xml：

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/dispatcher-servlet.xml</param-value>
</context-param>

...

<servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <!--Configure DispatcherServlet to use AnnotationConfigWebApplicationContext instead of default XmlWebApplicationContext.--> 
    <init-param>
        <param-name>contextClass</param-name>
        <param-value>org.springframework.web.context.support.AnnotationConfigWebApplicationContext</param-value>
    </init-param>
     <!--Custom web configuration annotated class.  -->
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>ca.mat8j8.configuration.WebConfiguration</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

我清空dispatcher-servlet.xml，并创建WebConfiguration：

@Configuration
@ComponentScan(basePackages = { "ca.mat8j8.controller" })
public class WebConfiguration extends WebMvcConfigurationSupport {

@Bean
public ViewResolver viewResolver() {
    final FreeMarkerViewResolver resolver = new FreeMarkerViewResolver();
    resolver.setCache(true);
    resolver.setPrefix("");
    resolver.setSuffix(".ftl");
    return resolver;
}

@Bean
public FreeMarkerConfigurer freemarkerConfig() throws IOException, TemplateException {
    FreeMarkerConfigurationFactory factory = new FreeMarkerConfigurationFactory();
    factory.setTemplateLoaderPath("/WEB-INF/views/");
    final FreeMarkerConfigurer configurer = new FreeMarkerConfigurer();
    configurer.setConfiguration(factory.createConfiguration());
    return configurer;
}
}

在启动时，我可以看到它通过我的java webConf（断点）。在我的脑海中，它应该做同样的事情，但是当我现在尝试到达我的家时＆＃34; view（使用xml conf），我觉得非常有趣：

GRAVE: Servlet.service() for servlet [dispatcher] in context with path [] threw exception [Could not resolve view with name 'home' in servlet with name 'dispatcher'] with root cause
javax.servlet.ServletException: Could not resolve view with name 'home' in servlet with name 'dispatcher'
at org.springframework.web.servlet.DispatcherServlet.render(DispatcherServlet.java:1211)
at org.springframework.web.servlet.DispatcherServlet.processDispatchResult(DispatcherServlet.java:1011)
at org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:955)
at org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:877)
at org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:966)
.....

有关信息，我使用tomcat 8，java 8和spring 4.1.5。

感谢您到目前为止阅读，提前感谢您的答案; - ）

Spring ViewResolver：xml conf ok，java中的SAME失败

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