Question

我想存储一些关于对象的额外数据（在本例中为配方），而不将其存储在对象本身中。这样做的最佳方式是什么？

这是一个简单的例子。我在建筑上做错了吗？

var recipes = {
    scones: {egg:2, milk: 5},
    pancakes: {eggs:3, milk: 2}
}

var recipesCooked = {
    scones: 0,
    pancakes: 0
}

function makeRecipe(recipe){

  // I don't want to have to do this loop every time.
  // Is there a better way of storing this data??
  for(var key in recipes) {
    if(recipes.hasOwnProperty(key) && recipes[key] === recipe){
      recipesCooked[key]++;
    }
  }
  //...snipped...make the recipe
}

makeRecipe(recipes.pancakes);
//recipesCooked.pancakes should be 1

换句话说：我需要一些方法将额外数据（recipesCooked）绑定到正确的配方，而我知道这样做的唯一方法是使用相同的密钥。但这看起来很糟糕，特别是因为我必须重复修改食谱以找到密钥的名称。

Answer 1

你需要传递整个食谱吗？你能不能把密钥传递进去？

function makeRecipe(key){
    var recipe = recipes[key];
    if (recipe != null && recipesCooked[key] != null)) {
       recipesCooked[key]++
       //...snipped...make the recipe
    }
}

Answer 2

也许您需要更改makeRecipe的签名。没有必要成为一个循环：

var recipes = {
    scones: {egg:2, milk: 5},
    pancakes: {eggs:3, milk: 2}
}

// no need for properties, [makeRecipe] takes care of that
var recipesCooked = { };

// parameter recipe should be a string
function makeRecipe( recipe ){
  if (!recipes[recipe]) { throw 'recipe ' + reicpe + ' not found'; }
  if (recipe in reicpesCooked) { recipesCooked[recipe] += 1; }
  else { recipesCoocked[reciped] = 1; }
  // and start cooking
}

makeRecipe('scones');

存储有关对象的额外数据

2 个答案: