有没有办法强制链接器使用函数名而不是序数来导入函数？

Question

创建DLL项目

void foo() {
    printf("foo");
}

DEF

LIBRARY
    EXPORTS
        foo @ 1

创建客户项目

void foo();
int _tmain(int argc, _TCHAR* argv[])
{
    foo();
    return 0;
}

客户端可执行文件的导入表。

导入表中缺少函数名称。

你能告诉我，有没有办法强制使用链接器使用函数名？

Answer 1

创建第二个没有序号的导入库：

>type foo.names.def
LIBRARY foo.dll
EXPORTS
    foo

>lib /nologo /def:foo.names.def /machine:x86
   Creating library foo.names.lib and object foo.names.exp

用法示例：

>type test.c
void foo();

int main()
{
        foo();
        return 0;
}

>cl /nologo test.c /link foo.names.lib
test.c

>dumpbin /nologo /imports:foo.dll test.exe

Dump of file test.exe

File Type: EXECUTABLE IMAGE

  Section contains the following imports:

    foo.dll
                40C108 Import Address Table
                410AA0 Import Name Table
                     0 time date stamp
                     0 Index of first forwarder reference

                    0 foo

将此与您使用“原始”导入库时获得的结果进行对比：

>cl /nologo test.c /link foo.lib
test.c

>dumpbin /nologo /imports:foo.dll test.exe

Dump of file test.exe

File Type: EXECUTABLE IMAGE

  Section contains the following imports:

    foo.dll
                40C108 Import Address Table
                410AA0 Import Name Table
                     0 time date stamp
                     0 Index of first forwarder reference

                      Ordinal     1