Question

我有一张表如下

 id       | name  | action_date | user_id 
 1        | Jhon  | 2014-03-1   |  2
 2        | Smith | 2014-03-03  | 3
 2        | Jhon  | 2014-04-2   |  2
 3        | Jhon  | 2014-06-3  |  2

我想从3月到4月选择所有行动的用户，并在此之后停止执行任何操作？在这种情况下，Smith使用user_id 3
我尝试过SQL但没有运气！

我也试过像SQL一样使用mysql_row等效方法，请海这个

SET @row_number = 0;
SELECT 
    @row_number:=CASE
        WHEN @customer_no = user_id THEN 
                    CASE when
                    DATE(action_date) >'2009-07-23' 
                    AND DATE(action_date) <'2009-07-25'
                    THEN
                     @row_number + 1
                    ELSE 211 END
        ELSE 1
    END AS Customer_Number,
    @customer_no:=user_id as Customers_id,
    action_date
FROM
    orders
ORDER BY Customers_id;

任何只使用Mysql的想法。

Answer 1

一种方式：

SELECT   name
FROM     my_table
GROUP BY name
HAVING   SUM(action_date BETWEEN '2014-03-01' AND '2014-04-30')
     AND MAX(action_date) <= '2014-04-30'

Answer 2

SELECT tab.* FROM tab 
inner join 
( SELECT min(dt) as mindt, max(dt) as maxdt, user_id FROM tab 
group by user_id
having mindt >= '2014-03-01' and maxdt <= '2014-04-30' )  t
on
tab.user_id = t.user_id

Answer 3

您可以使用＆＃34; NOT IN＆＃34; ，尝试此查询除了来自另一个表或同一个表的某些值

    SELECT table.`user_id` FROM table 
          WHERE (`action_date` between STR_TO_DATE('01-03-2014','%d-%m-%Y') and STR_TO_DATE('30-04-2014','%d-%m-%Y') ) 
        AND table.`user_id` NOT IN  
            (SELECT table.`user_id` FROM table 
                 WHERE `action_date` > STR_TO_DATE('30-04-2014','%d-%m-%Y'))
GROUP BY table.`user_id`

或者如果您想在一个查询中创建它：

SELECT min(action_date) as min_date, max(action_date) as max_date, user_id FROM orders_test 
where action_date > '2014-03-01'
group by user_id
having min_date >= '2014-03-01' and max_date <= '2014-04-30'

Answer 4

从tb_name中选择*，其中action_date位于STR_TO_DATE（＆＃39; 01,03,2014＆＃39;，＆＃39;％d，％m，％Y＆＃39;）和STR_TO_DATE（＆＃39; 30， 03,2014＆＃39;％，％m，％Y＆＃39;）;

I assume here that tb_name is the name of your table.

and you can read more on mysql dates

http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html

Answer 5

尝试这种方法......那应该......

SELECT user_id
FROM (
 SELECT user_id, STR_TO_DATE(action_date,'%Y-%m-%d') as actionDate, RIGHT( GROUP_CONCAT( DATE( STR_TO_DATE(action_date,'%Y-%m-%d') ) 
  SEPARATOR  ',' ) , 10 ) AS last_action
  FROM  `table` 
 WHERE actionDate > '2014-03-01'
 GROUP BY user_id
)last_action_selection
WHERE last_action <  '2014-04-30'

Answer 6

这是查询：

SELECT b.*
FROM orders b                              # "b" for "between"
  LEFT JOIN orders a                       # "a" for "after"
      ON b.user_id = a.user_id
      AND '2014-05-01' <= a.action_date    # "a" is after May 1st, 2014
WHERE a.user_id IS NULL                    # there is no "after April 1st"
  AND b.action_date BETWEEN '2014-03-01' AND '2014-04-30'

它将orders表作为b（“b”代表“between”）与其自身别名为a（“a”代表“after”）。来自b的每一行都与来自a的所有行配对，这些行具有与2014年5月1日之后user_id相同的action_date（同一用户的订单）。

LEFT JOIN确保b中的所有行都出现在已加入的结果集中。如果在b中找不到匹配的行，则会使用一整行NULL值。

where条件b.action_date BETWEEN '2014-03-01' AND '2014-04-30'仅保留2014年3月和4月发生的b的订单，条件a.user_id IS NULL过滤掉所有在联接中有对的行（即同一个用户也在5月1日之后订购了。

查询返回表order中的行列表。如果您只需要字段user_id，则需要添加DISTINCT以删除重复值：

SELECT DISTINCT user_id
...

Answer 7

试试这个

SELECT name FROM my_table WHERE
action_date BETWEEN '2014-03-01' AND '2014-04-30'
HAVING MAX(action_date) <= '2014-04-30'
GROUP BY name

根据条件过滤Mysql结果

7 个答案: