Question

我有一个如下程序：

CREATE PROCEDURE studentpvt2
AS
BEGIN

SELECT 
     TOP 1 StudentName, 
     EC1,
     EC2,
     EC3,
     EC4,
     EC5,
     TotalMarks=EC1+EC2+EC3+EC4+EC5 
 FROM Student pivot
(
SUM (Marks) FOR subject IN ([EC1],[EC2],[EC3],[EC4],[EC5],[TotalMarks])
)
AS pivotTable ORDER  BY TotalMarks DESC

SELECT 
     TOP 1 StudentName,
     EC1,
     EC2,
     EC3,
     EC4,
     EC5,
     TotalMarks=EC1+EC2+EC3+EC4+EC5 
 FROM Student pivot
(
SUM (Marks) FOR subject IN ([EC1],[EC2],[EC3],[EC4],[EC5],[TotalMarks])
)
AS pivotTable ORDER  BY TotalMarks ASC;

END

执行此操作时输出如下：

studentName EC1 EC2 EC3 EC4 EC5 TotalMarks
  Smita     76  45  67  56  76  320   

studentName EC1 EC2 EC3 EC4 EC5 TotalMarks
  Rajesh    34  56  12  45  23  170

我希望他们在一张表中显示两条记录，所以请帮助我如何获得该输出。这是我的第一个问题，如果有任何不妥，请原谅。

原始表是：

StudentID StudentName Subject Marks 1 Savita EC1 50 1 Savita EC2 55 1 Savita EC3 45 1 Savita EC4 34 1 Savita EC5 23 2 Rajesh EC1 34 2 Rajesh EC2 56 2 Rajesh EC3 12 2 Rajesh EC4 45 2 Rajesh EC5 23 3 Smita EC1 76 3 Smita EC2 45 3 Smita EC3 67 3 Smita EC4 56 3 Smita EC5 76 4 Rahul EC1 66 4 Rahul EC2 34 4 Rahul EC3 22 4 Rahul EC4 18 4 Rahul EC5 33

Answer 1

使用UNION或UNION ALL。您还应该将ORDER BY更改为WHERE子句以防止出错。见下文：

CREATE PROCEDURE studentpvt2
AS
BEGIN

SELECT 
     TOP 1 StudentName, 
     EC1,
     EC2,
     EC3,
     EC4,
     EC5,
     TotalMarks=EC1+EC2+EC3+EC4+EC5 
 FROM Student pivot
(
SUM (Marks) FOR subject IN ([EC1],[EC2],[EC3],[EC4],[EC5],[TotalMarks])
)
AS pivotTable WHERE TotalMarks = (
                 SELECT TOP 1 Sum(Marks) s_m
                 FROM   Student 
                 GROUP  BY StudentName
                 ORDER  BY s_m DESC)
UNION ALL
SELECT 
     TOP 1 StudentName,
     EC1,
     EC2,
     EC3,
     EC4,
     EC5,
     TotalMarks=EC1+EC2+EC3+EC4+EC5 
 FROM Student pivot
(
SUM (Marks) FOR subject IN ([EC1],[EC2],[EC3],[EC4],[EC5],[TotalMarks])
)
AS pivotTable WHERE TotalMarks = (
                 SELECT TOP 1 Sum(Marks) s_m
                 FROM   Student 
                 GROUP  BY StudentName
                 ORDER  BY s_m ASC);

END

Answer 2

CREATE PROCEDURE studentpvt2
AS
BEGIN

SELECT * FROM (SELECT 
     TOP 1 StudentName, 
     EC1,
     EC2,
     EC3,
     EC4,
     EC5,
     TotalMarks=EC1+EC2+EC3+EC4+EC5 
 FROM Student pivot
(
SUM (Marks) FOR subject IN ([EC1],[EC2],[EC3],[EC4],[EC5],[TotalMarks])
)
AS pivotTable order by [TotalMarks])A


UNION ALL

SELECT * FROM (SELECT 
     TOP 1 StudentName, 
     EC1,
     EC2,
     EC3,
     EC4,
     EC5,
     TotalMarks=EC1+EC2+EC3+EC4+EC5 
 FROM Student pivot(
SUM (Marks) FOR subject IN ([EC1],[EC2],[EC3],[EC4],[EC5],[TotalMarks])
)
AS pivotTable order by [TotalMarks] DESC)B

END

Answer 3

不是在两个Union查询之间使用pivot，而是使用单个数据透视并过滤旋转后的最大值和最小值

您无法在order by或Union

中间使用Union All

SELECT *
FROM   (SELECT StudentName,
               EC1,
               EC2,
               EC3,
               EC4,
               EC5,
               TotalMarks=EC1 + EC2 + EC3 + EC4 + EC5
        FROM   Yourtable
               PIVOT ( Sum(Marks)
                     FOR subject IN([EC1],
                                    [EC2],
                                    [EC3],
                                    [EC4],
                                    [EC5],
                                    [TotalMarks]) ) AS pivotTable) a
WHERE  TotalMarks = (SELECT TOP 1 Sum(Marks) s_m
                     FROM   Yourtable
                     GROUP  BY StudentName
                     ORDER  BY s_m DESC)
        OR TotalMarks = (SELECT TOP 1 Sum(Marks) s_m
                         FROM   Yourtable
                         GROUP  BY StudentName
                         ORDER  BY s_m ASC)

或使用stacked CTE

;WITH min_cte
     AS (SELECT TOP 1 StudentName,
                      EC1,EC2,EC3,EC4,EC5,
                      TotalMarks=EC1 + EC2 + EC3 + EC4 + EC5
         FROM   Yourtable
                PIVOT ( Sum(Marks)
                      FOR subject IN([EC1],
                                     [EC2],
                                     [EC3],
                                     [EC4],
                                     [EC5],
                                     [TotalMarks]) ) AS pivotTable
         ORDER  BY TotalMarks ASC),
     max_cte
     AS (SELECT TOP 1 StudentName,
                      EC1,EC2,EC3,EC4,EC5,
                      TotalMarks=EC1 + EC2 + EC3 + EC4 + EC5
         FROM   Yourtable
                PIVOT ( Sum(Marks)
                      FOR subject IN([EC1],
                                     [EC2],
                                     [EC3],
                                     [EC4],
                                     [EC5],
                                     [TotalMarks]) ) AS pivotTable
         ORDER  BY TotalMarks DESC) SELECT *
FROM   min_cte
UNION ALL
SELECT *
FROM   max_cte

如何在一个表中显示两个记录？

3 个答案: