Question

我需要一个代表黄道十二宫日历的清单。它是接受用户输入月和日的小程序的一部分。有没有办法做到这一点？我仍然处于逻辑尿布中，当谈到python时，它可能还在子宫里。我也已经被告知我不是非常pythonic ...我知道。

month = ["January","February","March","April","May","June",
     "July","August","September","October","November","December"]


#The following is the list I am attempting to create
#I need it to represent 365 days but I don't want to type
#each zodiac sign thirty times. It would look ridiculous
#and would probably be considered illogical.

zodiac = [['Capricorn']*19,['Aquarius']*30,['Pisces']*30]

#You probably know with out running the above list that it only
#has three elements zodiac[0],[1],[2]... I need it to have 79.
#Is this possible?

dayOfYear= [0,31,59,90,120,151,181,212,243,273,304,334]
zodiacDay = int

birthmonth = int(raw_input('Enter your birth month(1-12): ')) - 1
while birthmonth <= 12:
    birthday = int(raw_input('Enter your birth day(1-31): '))
    while birthday < 32:
        zodiacDay = dayOfYear[birthmonth] + birthday
        print"""
You were born on the %r day of the year,
which is the %r of %s. Your Zodiac sign is %s.
""" % (dayOfYear[birthmonth] + birthday,birthday,month[birthmonth],
   zodiac[zodiacDay])
    birthmonth = int(raw_input('Enter your birth month(1-12): ')) - 1

Answer 1

关于如何组合包含固定值的多个列表的主要问题：

zodiac = ['Capricorn']*19 + ['Aquarius']*30 + ['Pisces']*30

等。这将连接字符串列表，而不是创建字符串列表列表。还有其他方法，但在我看来这是最简单的，非常适合这种情况。

对于其他建议 - 如果您希望使用一年中的某一天作为预先计算的值列表的索引，您可能会发现内置datetime.date类的toordinal方法很有用。< / p>

正如Marcin建议的那样，使用范围通常是我如何解决这类问题 - 按最早的数字存储符号值的索引，并遍历该列表，直到找到小于或等于当天的值给出的数字。但使用365元素列表来存储值并不可怕。

如果你这样做不仅仅是一个学习练习，那么一定要考虑闰年。我对占星术的了解不足以确切知道在那里推荐什么。

如何在不键入每个变量的情况下创建包含多个相同变量的列表？（python）

1 个答案: