Question

代码看起来像这样

public GetPortfoliosResponse retrievePortfolios(RequestIdentityInfo requestIdentityInfo, GetPortfoliosRequest getPortfoliosRequest) {
    PortfolioReferenceParameter portfolioReferenceParameter = new PortfolioReferenceParameter();
    //some code
    List<Portfolio> portfolios = portfolioReferenceParameter.getPortfolios();
}

在我的测试课中，我正在做这样的事情

@Mock
private PortfolioReferenceParameter portfolioReferenceParameter;
@Before
public void setup() {
    MockitoAnnotations.initMocks(this);
    List<Portfolio> portfolios = new ArrayList<Portfolio>();
    //code to build the list
    when(portfolioReferenceParameter.getPortfolios()).thenReturn(portfolios);
}

但这似乎不起作用。

当我调用serviceimpl方法时，它仍然使用在该方法中本地创建的PortfolioReferenceParameter的实际对象。如何用我的对象模拟该对象？

Answer 1

Mockito不支持模拟构造函数 - 您需要使用PowerMock whenNew - 请参阅https://code.google.com/p/powermock/wiki/MockitoUsage13。

更好的方法是重构您的retrievePortfolios方法，将PortfolioReferenceParameter的实例作为参数并在测试中注入模拟

public class AppTest {

    @Mock
    private PortfolioReferenceParameter referenceParam;

    private List portfolios = new ArrayList();

    @Before
    public void setUp() {
        when(referenceParam.getPortfolios())
          .thenReturn(portfolios);
    }

    @Test
    public void testApp() {
        GetPortfoliosResponse response = retrievePortfolios(requestIdentityInfo, getPortfoliosRequest, referenceParam);
        // assert response details
    }
}

如何模拟serviceimpl类方法中的对象

1 个答案: