Django View Counter

时间:2015-03-03 13:13:36

标签: python django counter

在views.py中制作视图计数器功能的最佳方法是什么?

我确实在Django文档中找到了F()表达式,但是如何让它工作或者更好的想法?

提前谢谢

def watch_video(request, slug):

    video = get_object_or_404(Video, slug=slug)

    template = "single_video.html" 

    #if this function will run , + 1 in Video.views ?


    return render(request,template,{"video":video})

我的模特:

class Video(models.Model):

    video_id = models.CharField(max_length=150)
    title = models.CharField(max_length=150)
    slug = AutoSlugField(populate_from="title")
    description = models.TextField(blank=True)
    views = models.PositiveIntegerField(default=0)
    likes = models.PositiveIntegerField(default=0)
    category = models.ForeignKey("VideoCategory")
    created = models.DateTimeField(auto_now_add=True)
    modified = models.DateTimeField(auto_now=True)
    tags = models.ManyToManyField("Tag")


    def __str__(self):

        return self.title

    def get_absolute_url(self):

        return reverse("watch", kwargs={"slug" : self.slug})

2 个答案:

答案 0 :(得分:6)

调用查询集上的update(),过滤单个视频:

from django.db.models import F

Video.objects.filter(pk=video.pk).update(views=F('views') + 1)
video.views += 1 # to show valid counter in the template

答案 1 :(得分:0)

在模型中增加函数非常简单,将视图递增1

然后在views.py中调用每次用户访问该模型页面时增加功能并保存它!