我有一个如下列表
['item1', 'item2', 'item3', 'item4']
我想从上面的列表中构建一个字典,如下所示
{
"item1": {
"item2": {
"item3": "item4"
}
}
}
列表中的项目数是动态的。字典将是嵌套字典,直到它到达列表的最后一个元素。 在python中有没有办法做到这一点?
答案 0 :(得分:9)
简单的单行:
a = ['item1', 'item2', 'item3','item4']
print reduce(lambda x, y: {y: x}, reversed(a))
为了更好地理解,上面的代码可以扩展为:
def nest_me(x, y):
"""
Take two arguments and return a one element dict with first
argument as a value and second as a key
"""
return {y: x}
a = ['item1', 'item2', 'item3','item4']
rev_a = reversed(a) # ['item4', 'item3', 'item2','item1']
print reduce(
nest_me, # Function applied until the list is reduced to one element list
rev_a # Iterable to be reduced
)
# {'item1': {'item2': {'item3': 'item4'}}}
答案 1 :(得分:4)
使用递归:
In [10]: src = ['item1', 'item2', 'item3','item4']
In [11]: def list2dict(src_list):
if len(src_list) > 1:
return {src_list[0] : list2dict(src_list[1:])}
else:
return src_list[0]
....:
In [12]:
In [12]: list2dict(src)
Out[12]: {'item1': {'item2': {'item3': 'item4'}}}
答案 2 :(得分:3)
使用reduce()
function访问和设置元素:
try:
# Python 3 moved reduce to the functools module
from functools import reduce
except ImportError:
# Python 2 reduce is a built-in
pass
def get_target(d, keys):
return reduce(lambda d, k: d.setdefault(k, {}), keys, d)
def set_target(d, keys, value):
parent = get_target(d, keys[:-1])
parent[keys[-1]] = value
result = {}
set_target(result, yourlist[:-1], yourlist[-1])
get_target()
和set_target()
函数可在已构建的嵌套结构上重用,它们不限于从头构建字典。我从earlier, related post改编了get_target()
。
演示:
>>> def get_target(d, keys):
... return reduce(lambda d, k: d.setdefault(k, {}), keys, d)
...
>>> def set_target(d, keys, value):
... parent = get_target(d, keys[:-1])
... parent[keys[-1]] = value
...
>>> result = {}
>>> yourlist = ['item1', 'item2', 'item3', 'item4']
>>> set_target(result, yourlist[:-1], yourlist[-1])
>>> result
{'item1': {'item2': {'item3': 'item4'}}}