Question

我试图在matplotlib中创建一个这样的Gauge：

http://www.highcharts.com/demo/gauge-solid

它几乎可以工作。这是到目前为止的代码：

    import numpy as np
    import matplotlib.pyplot as plt
    import matplotlib.animation as animation
    from matplotlib.patches import Wedge
    from matplotlib.backends.backend_qt4agg import FigureCanvasQTAgg as                 FigureCanvas

    from matplotlib.figure import Figure
    import sys,os
    from PyQt4 import QtGui,QtCore

    class MyMplCanvas(FigureCanvas):
        """Ultimately, this is a QWidget (as well as a FigureCanvasAgg, etc.)."""
        def __init__(self, parent=None):
            self.fig = Figure(facecolor='#DBE0E4')
            self.axes = self.fig.add_subplot(111,axisbg='#DBE0E4')
            self.axes.axis('off')
            #here I create the contour of the gauge
            #the two horizontal lines
            x1=[-1,-0.6]
            x2=[0.6,1.0]
            y=[0.004,0.004]
            self.axes.plot(x1,y,color='#646464')
            self.axes.plot(x2,y,color='#646464')
            #and the 2 circles(inner and outer)
            circle1=plt.Circle((0,0),radius=1,fill=False)
            circle1.set_edgecolor('#646464')
            circle1.set_facecolor(None)

            circle2=plt.Circle((0,0),radius=0.6,fill=False)
            circle2.set_edgecolor('#646464')
            circle2.set_facecolor(None)
            self.axes.add_patch(circle1)
            self.axes.add_patch(circle2)

            #Scaling of the figure
            self.axes.axis('scaled')
            self.axes.set_xlim(-1.1,1.1)
            self.axes.set_ylim(0,1.1)

            FigureCanvas.__init__(self, self.fig)
            self.setParent(parent)

            FigureCanvas.updateGeometry(self)


    class Gauge(MyMplCanvas):
        def __init__(self,meter,parent=None):
            MyMplCanvas.__init__(self)


            self.patches=[]
            #here I create the wedge to start
            self.wedge=Wedge((0,0),0.99,1,179,width=0.38,facecolor='#FF0000')
            self.patches.append(self.wedge)
            self.timeClear=0
            self.update_figure()
            #self.Online_meter=meter
            #here starts the update
            timer=QtCore.QTimer(self)
            timer.timeout.connect(self.update_figure)
            timer.start(5000)

        def update_figure(self):
            #here is the update command
            #every 5 sec, I call value from a measurement instrument
            #here I let the program generate random values
            self.timeClear=self.timeClear+1
            #new_data=self.Online_meter.__call__()
            self.wedge.set_theta1(180-np.random.random(1)*10/10*179)
            self.axes.add_patch(self.wedge)    
            self.draw()

直到现在，这都有效。编写代码是为了将其作为一个小部件添加到PyQt 4程序中。它们只留下一个问题：当值更新时，仪表突然改变，但我想看到仪表更新（所以我想看到楔形的角度改变，所以缓慢移动）我希望你伙计们可以帮助我。或者他们已经是一个很好的库，可以在pyqt4 GUI中插入好看的仪表？

感谢您提前帮助我！

Answer 1

我自己解决了。在上面的代码中，程序本身生成一个介于0-10之间的数字（在update_figure方法中）。这个数字是四个。

这意味着在楔子上：

    theta1 = 180-number/10*179  
    #as always theta2:
    theta2 =180

5秒后程序生成另一个数字（例如：6.5）

这意味着楔子的属性必须改变。

通过在对象Gauge的update_figure方法中添加for循环：

    def update_figure(self):

            self.timeClear=self.timeClear+1
            #the old value becomes temp
            temp=self.new_data
            self.number=np.random.random(1)*10
            self.new_data=180-self.number/10*179

            step=(self.new_data-temp)/10
            for x in range(10):

                self.wedge.set_theta1(temp+step*x)
                self.axes.add_patch(self.wedge)    
                time.sleep(1/10)
                self.draw()

通过取旧数和新数之间的差值并除以10.您可以通过添加此for循环轻松地动态更改量表，并让楔形自己绘制1次（theta1在10中变化）从旧号码到新号码的步骤，睡眠时间为100毫秒。如果这个解释不明确，请问我，我会再尝试解释一下。

matplotlib仪表动态更新

1 个答案: