HTML

Question

在while循环中，我有医生姓名，专家和我的数据库付款。每位医生都有<input type="button">名为＆＃34;做过＆＃34;。我希望当我按下按钮联系特定医生时，$row3['did']的值将发送到我的contact.php页面。但是我无法理解将它放在<input type="button">中的哪个位置，以便我可以识别按下哪个按钮并将其值发送到contact.php。

while($row3 = mysql_fetch_array($result3))
{       
        ?>      
        <div class="col_1_of_4 span_1_of_4">
        <div class="title-img">
        <div class="title"><img src="images/Crystal_Clear_user.gif" alt=""></div>
        <!--<div class="title-desc"><p>FACILITY 1</p></div>-->
        <div class="clear"></div> 
        </div>
        <h4 class=head>Doctor name: <?php echo $row3['dName'];?></h4>
        <p>Specialist: <?php echo $row3['specialist'];?></p>
        <p>Payment: <?php echo $row3['payment'];?></p>


        <hr>

            <div id='contact-form'>
                <a href="#" class="btn btn-primary">more</a>

                <!--<button id="findHelp" class="btn btn-primary"><a href="?did=<?php// echo $row3['did'];?>"  >Find help</a></button>-->
                <!--<a href="data/contact.php?did=<?php //echo $row3['did'];?>"  ></a>-->
                <!--<input type='button' name='contact' id='contact' value="Message" class='contact demo btn btn-primary'/>-->

                <form method='post' action='contact.php'>
                    <input type='button' name='did' id='did' value="Message" class='contact demo btn btn-primary'/>
                </form>


            </div>

            <!-- preload the images -->
            <div style='display:none'>
                <img src='images/loading.gif' alt='' />
            </div>

        </div>
<?php
}
?>

Answer 1

无需添加表单。单击按钮时，只需发送带链接的id，并在联系.php页面上获取该ID ..

或使用如下

<script src="jquery.js" type="text/javascript"></script>
<script>
$(document).ready(function() {
       $('.contact').click(function(){
            var this_rel=$(this).attr('rel');
            location.href="contact.php?id="+this_rel;
       });
    });
</script>


 <input type='button' name='did' id='did' value="Message" class='contact demo btn btn-primary' rel="<?php echo $row3['did'];?>"/>

Answer 2

尝试if(isset($_POST['button_name']) && $_POST['button_name'] === 'button_value')

Answer 3

在表单中使用隐藏值，并在那里分配医生详细信息

<form method="post" action="contact.php">

   <input type="hidden" name="thedoctor" value="<?php echo $row3['did'];?>"/>  
   <input type="button" name="did" id="did" value="Message" class="contact demo btn btn-primary"/>

</form>

然后按$button_clicked = $_POST['thedoctor']

找到所选按钮

Answer 4

这将是您的PHP代码

<?php
while($row3 = mysql_fetch_array($result3))
{       
        ?>      
        <div class="col_1_of_4 span_1_of_4">
        <div class="title-img">
        <div class="title"><img src="images/Crystal_Clear_user.gif" alt=""></div>
        <!--<div class="title-desc"><p>FACILITY 1</p></div>-->
        <div class="clear"></div> 
        </div>
        <h4 class=head>Doctor name: <?php echo $row3['dName'];?></h4>
        <p>Specialist: <?php echo $row3['specialist'];?></p>
        <p>Payment: <?php echo $row3['payment'];?></p>


        <hr>

            <div id='contact-form'>
                <a href="#" class="btn btn-primary">more</a>


                    <input type='button' name='did' id='did' value="Message" class='contact demo btn btn-primary' rel="<?php echo $row3['did'];?>"/>


            </div>

            <!-- preload the images -->
            <div style='display:none'>
                <img src='images/loading.gif' alt='' />
            </div>

        </div>
<?php
}
?>

以上，放了一些jquery代码

<script src="jquery.js" type="text/javascript"></script>
<script>
$(document).ready(function() {
       $('.contact').click(function(){
            var this_rel=$(this).attr('rel');
            location.href="contact.php?id="+this_rel;
       });
    });
</script>

别忘了写数据库的查询，因为那不是你的例子，这就是我没有提到的原因。还要将jquery.js添加到适当的位置，以便运行jquery代码。请这个技巧让我知道..

Answer 5

只需使用buttons：

HTML

<form method="POST">
    <button type="submit" name="btn_action_1" value="abc">Message</button>
    <button type="submit" name="btn_action_1" value="def">Message</button>
    <button type="submit" name="btn_action_1" value="ghi">Message</button>
    <button type="submit" name="btn_action_1" value="jkl">Message</button>
    <button type="submit" name="btn_action_2" value="123">Message</button>
    <button type="submit" name="btn_action_3" value="456">Message</button>
</form>

PHP

<?php
    if(isset($_POST['btn_action_1'])) {
        echo 'btn_action_1 was pressed with value: '. $_POST['btn_action_1'];
    }
    if(isset($_POST['btn_action_2'])) {
        echo 'btn_action_2 was pressed with value: '. $_POST['btn_action_2'];
    }

如何识别按下哪个按钮并将其发送到服务器？

5 个答案:

HTML

PHP