sql字符串中的随机字符

Question

我需要用随机字母或数字替换所有?符号。

所以我尝试了这个：

REPLACE (RGFLT, '?', LEFT(NEWID(), 1))

此代码不够好，因为它每行生成一次随机符号。我需要的是字符串中每个?的随机符号。

数据样本：

AA ?????
BCZ ???Z?
B?? ???

Answer 1

设置数据

DECLARE @t table (
   a varchar(50)
);

INSERT INTO @t (a)
  VALUES ('A?A??')
       , ('BBBBB')
       , ('C??CC')
       , ('??DD?')
       , ('?????')
       , ('?')
       , ('ABCDEF??ASG?AG?GE?E?£%$ H?EHH?SN?S SA? ? !??" ')
;

---

方法1 - 递归CTE

; WITH x AS (
  SELECT a As original_value
       , numbers.number As sequence
       , SubString(a, numbers.number, 1) As to_replace
       , Left(NewID(), 1) As replace_char
  FROM   @t As t
   LEFT
    JOIN dbo.numbers
      ON numbers.number BETWEEN 1 AND Len(t.a)
)
, y AS (
  SELECT original_value
       , sequence
       , CASE WHEN to_replace = '?' THEN replace_char ELSE to_replace END As to_use
  FROM   x As x1
)
, z AS (
  SELECT original_value
       , sequence
       , to_use
       , Cast(to_use As varchar(max)) As new_value
  FROM   y
  WHERE  sequence = 1 -- anchor

   UNION ALL

    SELECT z.original_value
         , y.sequence
         , y.to_use
         , z.new_value + y.to_use
    FROM   z
     INNER
      JOIN y
        ON y.original_value = z.original_value
       AND y.sequence - 1 = z.sequence
)
SELECT original_value
     , new_value
FROM   z
WHERE  sequence = Len(original_value)
;

[示例]结果：

original_value                                     new_value
-------------------------------------------------- ---------------------------------------------
?                                                  F
ABCDEF??ASG?AG?GE?E?£%$ H?EHH?SN?S SA? ? !??"      ABCDEF4DASG7AGFGE5E2£%$ H7EHHASN2S SAF 1 !77"
?????                                              CB347
??DD?                                              43DD2
C??CC                                              C31CC
BBBBB                                              BBBBB
A?A??                                              A7A99

这是它如何运作的主旨：

1. 使用数字表将原始值拆分为每个字符一行。
2. 计算出我们要替换的字符串（?）并为这些字符串生成随机字符。对于那些我们不想替换的人，请保留原始角色。
3. 使用递归基本上将字符串重新组合在一起1个字符
4. 过滤以显示“最终”值

---

方法2 - 东西（FORXML）

; WITH x AS (
  SELECT a As original_value
       , numbers.number As sequence
       , SubString(a, numbers.number, 1) As to_replace
       , Left(NewID(), 1) As replace_char
  FROM   @t As t
   LEFT
    JOIN dbo.numbers
      ON numbers.number BETWEEN 1 AND Len(t.a)
)
, y AS (
  SELECT original_value
       , sequence
       , CASE WHEN to_replace = '?' THEN replace_char ELSE to_replace END As to_use
  FROM   x As x1
)
SELECT DISTINCT
       original_value
     , Replace(Stuff((
         SELECT '|' + z.to_use
         FROM   y As z
         WHERE  z.original_value = y.original_value
         ORDER
             BY z.sequence
         FOR XML PATH(''))
       , 1, 1, ''), '|', '') As new_value
FROM   y
;

[示例]结果：

original_value                                     new_value
-------------------------------------------------- ---------------------------------------------
?                                                  5
?????                                              10A30
??DD?                                              7EDDC
A?A??                                              AEA23
ABCDEF??ASG?AG?GE?E?£%$ H?EHH?SN?S SA? ? !??"      ABCDEFE8ASGEAG0GEBE4£%$ H8EHH2SNCS SAE 1 !1E"
BBBBB                                              BBBBB
C??CC                                              C34CC

这是它如何运作的主旨：

步骤1＆amp; 2与方法1相同......

1. 使用用于字符串连接的[yucky！] Stuff(FOR XML) hack来强制将值重新组合成一个字符串值。

不漂亮，但它有效！

Answer 2

请注意，我做了以下假设

• 序列?字符的最大数量为5
• 如果你得到两个相同数量的?序列，则会被替换为相同的数字。例如，文本TEST ?? TEST ??将会像TEST 12 TEST 12
一样进行转换

由于解决方案不是动态的（您需要将其更改为适用于您的情况）。

---

DECLARE @DataSource TABLE
(
    [Text] VARCHAR(128)
);

INSERT INTO @DataSource ([Text])
VALUES ('AA ?????')
      ,('BCZ ???Z?')
      ,('B?? ???')
      ,('C?? ???')
      ,('D?? ???');


SELECT [Text]
      ,REPLACE(
            REPLACE(
                REPLACE(
                    REPLACE(
                        REPLACE([Text], '?????', LEFT(ABS(CHECKSUM(NEWID())) % 1000000 + 100000, 5))
                    , '????',LEFT(ABS(CHECKSUM(NEWID())) % 1000000 + 100000, 4))
                , '???',LEFT(ABS(CHECKSUM(NEWID())) % 1000000 + 100000, 3))
            , '??',LEFT(ABS(CHECKSUM(NEWID())) % 1000000 + 100000, 2))
        , '?',LEFT(ABS(CHECKSUM(NEWID())) % 1000000 + 100000, 1))
FROM @DataSource;