Question

*嗨我总是收到错误查询失败，但我没有在apache2日志是≤<

我想在不登录网站的情况下更改帐户密码。

希望有人能帮我解决这个问题。

//清理POST值

$login = clean($_POST['login']);

$email = clean($_POST['email']);

$newpw = clean($_POST['newpass']);

$cnewpw = clean($_POST['cnewpass']);





//Input Validations

if($login == '') {

    $errmsg_arr[] = 'Login ID missing';

    $errflag = true;

}

if($email == '') {

    $errmsg_arr[] = 'Email missing';

    $errflag = true;

}

if($newpw == '') {

    $errmsg_arr[] = 'Password missing';

    $errflag = true;

}

if($cnewpw == '') {

    $errmsg_arr[] = 'Confirm password missing';

    $errflag = true;

}

if( strcmp($newpw, $cnewpw) != 0 ) {

    $errmsg_arr[] = 'Passwords do not match';

    $errflag = true;

}

//检查重复的登录ID

if($login != '' && $email != '') {

    $qry = "SELECT * FROM t_account WHERE name='$login' AND email='$email'";

    $result = mysql_query($qry);

    if($result) {

        if(mysql_num_rows($result) < 1) {

            $errmsg_arr[] = 'Username and or Email is not in our system!';

            $errflag = true;

        }

        @mysql_free_result($result);

    } else {

        die("Query Failed");

    }





//Create update query

$qry = "UPDATE t_account SET (pwd, pw2) VALUES('".md5($_POST['newpass'])."','$newpw')";

$result = @mysql_query($qry);



//Check whether the query was successful or not

if($result) {

    header("location: register-success.html");

    exit();

}else {

    die("mysql_error");

}

}

＆GT;

*

Answer 1

您可以通过phpMyadmin更改密码。检查密码生成器代码。它必须是md5我猜。

Answer 2

输入if尝试打印$ query字符串的值后，在tour SQL客户端上复制粘贴IT并看看你得到了什么

Answer 3

您的Update-String的SQL语法不正确（至少在ANSI-SQL中）。

是

INSERT INTO table (col1,col2) VALUES...

或

UPDATE table set col1=val1, col2=val2 WHERE...

在Sql Database Update上查询失败

3 个答案: