Question

我正在尝试编写一个查询，其中我需要获取/计数在同一日期注册的记录。但问题是在mysql结构中created_date字段有＆＃34; datetime＆＃34;结构

让我举个例子

如果2015-02-25有5人注册，2015-02-11有6人注册。它将输出为

Sno. Date.           count
1)   2015-02-25        5  
2)   2015-02-11        6

以下是附加数据库行的示例，以便更好地理解 http://i.stack.imgur.com/iPeLl.png

Answer 1

SELECT date(created_at),count(*) FROM myTable GROUP BY date(created_at)

Answer 2

您的查询应该是这样的：

select date(created_at) created_at, count(*) from TABLE 
    group by date(created_at)

在日期之间选择

select date(created_at) created_at, count(*) from TABLE 
    where date(created_at) >= '2015-02-11' and date(created_at) <= '2015-02-25' 
    group by date(created_at)

使用between：

select date(created_at) created_at, count(*) from Mytable  
   where date(created_at) BETWEEN '2015-01-05' AND '2015-02-25' 
   group by date(created_at)

参考：count()

Answer 3

It might be the one that you expected.

SELECT
    DATE_FORMAT(created_at,"%Y-%m-%d") AS Date,
COUNT(*) AS count
FROM table_name
GROUP BY DATE_FORMAT(created_at,"%Y-%m-%d")
ORDER BY created_at DESC;

此查询将计算每天注册的人数。当然，最新的注册将首先出现。

Mysql查询通过从datetime中删除时间来计算结果

3 个答案: