Question

我有((?:[0-9]{1,3}[\.,]?)*[\.,]?[0-9]+)过滤掉java上字符串的价格，所以我把它们放在这样：

public static final String new_price = "((?:[0-9]{1,3}[\\.,]?)*[\\.,]?[0-9]+)";

final Pattern p = Pattern.compile(new_price, 0);
    final Matcher m = p.matcher(label);
    if (m.matches()) {
        Log.d(TAG, "found! good start");
        if (m.groupCount() == 1) {
            Log.d(TAG, "start match price" + " : " + m.group(0));
        }
        if (m.groupCount() == 2) {
            Log.d(TAG, "start match price" + " : " + m.group(1));
        }
    }

我在http://www.regexr.com/上运行了示例，但它从未在运行时找到匹配项。有什么想法??

Answer 1

您应该运行matches()而不是使用m.find()来搜索下一个匹配项（这应该在while循环中完成！）：

String new_price = "((?:[0-9]{1,3}[\\.,]?)*[\\.,]?[0-9]+)";
String label = "$500.00 - $522.30";
final Pattern p = Pattern.compile(new_price, 0);
final Matcher m = p.matcher(label);
while (m.find()) {
    System.out.println("found! good start");
    if (m.groupCount() == 1) {
        System.out.println("start match price" + " : " + m.group(0));
    }
    if (m.groupCount() == 2) {
        System.out.println("start match price" + " : " + m.group(1));
    }
}

<强>输出

found! good start
start match price : 500.00
found! good start
start match price : 522.30

过滤掉Java中的价格或成本

1 个答案: