Question

[{
    "SchoolId":"015-08-0034-009-37",
    "SubjectId":"08-0034-00613",
    "Student":[
        {"StudentId":"T-15981","StudentName":"John"},
        {"StudentId":"T-15982","StudentName":"Paul"}
    ]
}]

我的php json_encode中有一个像这样的json格式。我正在获取这样的数据

for (var i = 0; i < data.length; i++) {
     console.log(data.[i].SchoolId);
     console.log(data.[i].SubjectId);
}

我希望获得

的价值

 {"StudentId":"T-15981","StudentName":"John"},
 {"StudentId":"T-15982","StudentName":"Paul"}

如何获得两个条目的价值？赞赏任何想法

UPDATE

success: function(data) {


    for (var i = 0; i < data.student.length; i++) {
        console.log(data.student[i].StudentId);
        console.log(data.student[i].SchoolId);
    }
},

这是我通过将数据类型从json更改为html而从ajax响应获得的print_r。这是network>XHR>Response中的输出

Array
(
    [0] => Array
        (
            [SchoolId] => 015-08-0034-009-37
            [SubjectId] => 08-0034-00613
            [Student] => Array
                (
                    [0] => Array
                        (
                            [StudentId] => 015-08-0034-009-37
                            [firstname] => Chona
                            [lastname] => Sy
                            [middleinitial] => D
                        )

                    [1] => Array
                        (
                            [StudentId] => 015-08-0034-009-37
                            [firstname] => Alona
                            [lastname] => Sy
                            [middleinitial] => D
                        )

                )

        )

    [1] => Array
        (
            [SchoolId] => 015-08-0034-009-38
            [SubjectId] => 08-0034-00613
            [SupersededProperty] => Array
                (
                    [0] => Array
                        (
                            [StudentId] => 015-08-0034-009-36
                            [firstname] => Edith
                            [lastname] => Sy
                            [middleinitial] => D
                        )

                )

        )

)

Answer 1

您可以在FIDDLE

中找到工作示例

JS代码

var e = {
    "Student":[
        {"StudentId":"T-15981","StudentName":"John"},
        {"StudentId":"T-15982","StudentName":"Paul"}
    ], 
    "SchoolId":"015-08-0034-009-37",
    "SubjectId":"08-0034-00613",
};


for(var i=0; i<e.Student.length; i++){
  alert('StudentId = ' + e.Student[i].StudentId + '; StudentName = ' + e.Student[i].StudentName);   
}

Answer 2

var data = [{
    "SchoolId":"015-08-0034-009-37",
    "SubjectId":"08-0034-00613",
    "Student":[
        {"StudentId":"T-15981","StudentName":"John"},
        {"StudentId":"T-15982","StudentName":"Paul"}
    ]
}] 

for(var i=0; i<data[0].Student.length; i++){
  var StudentData = data[0].Student[i];
   alert(StudentData.StudentId); 
}

Answer 3

问题是你在数组中有一个数组。这导致json周围的方括号[{...}]。

Array
(
    [0] => Array
        (
...

你不应该回应第一个阵列。

例如，现在看起来像是

echo json_encode(array($data));

而你应该

echo json_encode($data);

作为最后的resorst尝试回显$ data [0];

另外see this

ajax jquery从php获取数据的值

3 个答案: