Question

在制作如何检查猜测是否正确的功能之后，我很难说出我想要的东西。

ntries = 0
while ntries < 10:
    ntries +=1
    if test_guess(code,guess)==True:
        print 'You win! You guessed the code in',ntries,'tries.'
    elif test_guess(code,guess)==False:
        guess = str(raw_input('Your guess: '))
print 'You lose!'

问题在于，当玩家成功猜到代码时，比如8次尝试，打印的结果是：

> You win! You guessed the code in 8 tries. 
> You win! You guessed the code in 9 tries. 
> You win! You guessed the code in 10 tries.
> You lose!

我意识到这是因为while循环表明当ntries仍然小于10时循环继续运行。我如何才能使它只在打赢时停止尝试次数并停在那里？ / p>

Answer 1

使用break声明中的if关键字突破您的循环。

顺便说一句：您的if-elif块过于冗长。由于test_guess正在返回一些真实的东西，你可以这样重写它。这也会将ntries变量移到else条件中，因为只有在实际猜测时才增加它，但是失败了。

if test_guess(code, guess):
    print 'You win!  You guess the code in', ntries, 'tries.'
    break
else:
    ntries += 1
    guess = str(raw_input('Your guess: '))

Answer 2

只需使用break

ntries = 0
    while ntries < 10:
    ntries +=1
    if test_guess(code,guess)==True:
        print 'You win! You guessed the code in',ntries,'tries.'
        break
    elif test_guess(code,guess)==False:
        guess = str(raw_input('Your guess: '))
print 'You lose!'

赢得比赛后如何结束循环？

2 个答案: